A zucchini plant in Darnell’s garden was 12 centimeters tall when it was first planted. Since then, it has grown approximately 0
2 answers:
Answer
(a) Find out the a rule to describe the function.
To prove
Let us assume that the days be represted by d .
Let us assume that the height of plant be represted by y.
As given
A zucchini plant in Darnell’s garden was 12 centimeters tall when it was first planted.
it has grown approximately 0.5 centimeter per day.
Than the function becomes
y = 12 + 0.5 × d
y = 12 + 0.5d
(b) Find out after how many days will the zucchini plant be 0.195 meter tall .
To prove
Let us assume that the days be represted by d .
As given
A zucchini plant in Darnell’s garden was 12 centimeters tall when it was first planted.
it has grown approximately 0.5 centimeter per day.
As
1meter = 100cm
0.195 meter convert into centimeter.
= 19.5cm
Than the equation becomes
12 + 0.5d = 19.5
0.5d = -12 + 19.5
0.5d = 7.5
d = 15 days
Therefore 15 days will the zucchini plant be 0.195 meter tall .
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Answer:
Step-by-step explanation:
Hello!
A regression model was determined in order to predict the number of earthquakes above magnitude 7.0 regarding the year.
^Y= 164.67 - 0.07Xi
Y: earthquake above magnitude 7.0
X: year
The researcher wants to test the claim that the regression is statistically significant, i.e. if the year is a good predictor of the number of earthquakes with magnitude above 7.0 If he is correct, you'd expect the slope to be different from zero: β ≠ 0, if the claim is not correct, then the slope will be equal to zero: β = 0
The hypotheses are:
H₀: β = 0
H₁: β ≠ 0
α: 0.05
The statistic for this test is a student's t:
The calculated value is in the regression output
This test is two-tailed, meaning that the rejection region is divided in two and you'll reject the null hypothesis to small values of t or to high values of t, the p-value for this test will also be divided in two.
The p-value is the probability of obtaining a value as extreme as the one calculated under the null hypothesis:
p-value:
As you can see to calculate it you need the information of the sample size to determine the degrees of freedom of the distribution.
If you want to use the rejection region approach, the sample size is also needed to determine the critical values.
But since this test is two tailed at α: 0.05 and there was a confidence interval with confidence level 0.95 (which is complementary to the level of significance) you can use it to decide whether to reject the null hypothesis.
Using the CI, the decision rule is as follows:
If the CI includes the "zero", do not reject the null hypothesis.
If the CI doesn't include the "zero", reject the null hypothesis.
The calculated interval for the slope is: [-0.11; -0.04]
As you can see, both limits of the interval are negative and do not include the zero, so the decision is to reject the null hypothesis.
At a 5% significance level, you can conclude that the relationship between the year and the number of earthquakes above magnitude 7.0 is statistically significant.
I hope this helps!
(full output in attachment)
