Answer:
There should be at most 24 lucky numbers in the third bag.
Step-by-step explanation:
Initially, there are 200 numbers. Two bags with 100 each. There are 31+18 = 49 lucky numbers. So there is a 49/200 = 0.245 probability that a randomly selected number from a random bag is the lucky number.
Now with 300 numbers, we want this probability to be lower than 24.5%. So we should solve the following rule of three:
200 - 49
300 - x



With the third bag, the probability will be the same if 73.5-49 = 24.5 lucky numbers are added. So there should be at most 24 lucky numbers in the third bag.
Answer:
if x=4 then y=18
Step-by-step explanation:
hope this helps
please mark brainliest ;)
Answer:
Step-by-step explanation:
If you need to do this by graphing, you need to change the format of each equation into slope intersect form
start with 3x-2y=-24
-2y=-3x-24
y=-3/2x+12
To graph this, the y intersect (where it crosses the y axis) is 12 and from there the slope is -3/2
For the next equation,
-3x-y=6
-y=3x+6
y=-3x-6
So the y intersect is -6 and the slope is -3.
Once you graph both of these, the point where both lines cross AKA the intersecion is the solution to the problem.