Answer:
A. h = 64
B. t = 4 -> 4 seconds
C. t = 1.5 -> 1.5 seconds
D. maximum height is 100 ft
E. The domain that makes sense for the function in this context is t
is any positive real number since time can not be negative.
Step-by-step explanation:
h = -16t2 + vt + 64
A. What tower platform height was the projectile launched from?
when the projectile was not launched, t = 0
h = -16(0)^2 + v(0) + 64 = 64
B. How long was the projectile in the air?
if the projectile lands, its height = 0 so substitute 0 for h
0 = -16(t)^2 + 48(t) + 64
= -16(t^2 - 3t - 4)
= -16(t - 4)(t + 1)
t = 4 or t = -1
Since time can not be negative, t = -1 can not be the answer. Therefore, the projectile lands when t = 4 or 4 seconds.
C. When did it reach its maximum height?
maximum -> t=-b/2a where in -16(t)^2 + 48(t) + 64, b = 48 and a = -16
t = -48/-32 = 1.5
D. What was its maximum height?
plug t = 1.5 into -16(t)^2 + 48(t) + 64
-16(1.5)^2 + 48(1.5) + 64 = -36 + 72 + 64 = 100
E. The domain that makes sense for the function in this context is t
is any positive real number since time can not be negative.
.
