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solong [7]
4 years ago
14

Find the excluded value of the rational expression A 2 B -3 C-2 D 0

Mathematics
1 answer:
almond37 [142]4 years ago
3 0
The excluded value is the <span>value that makes the denominator of a fraction equal to 0. So to find the excluded value you have to solve the following equation:
4x-8=0
4x=8
x=\frac{8}{4}=2
</span>
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In the United States, 7% of all registered voters belong to the Green party. A random sample of 50 registered voters is taken. U
Maksim231197 [3]

Answer:

The expected value of the sample proportion is of 0.07.

1. P(p < .02) = 0.0823

2. P(p > .15) = 0.0132

3. P(.05 < p < .09) = 0.4176

Step-by-step explanation:

This question is solved using the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

7% of all registered voters belong to the Green party. 50 voters:

This means that p = 0.07, n = 50

So, for the normal distribution:

\mu = 0.07, s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.07*0.93}{50}} = 0.036

The expected value of the sample proportion is of 0.07.

1. Determine P(p < .02).

This is the pvalue of Z when X = 0.02. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.02 - 0.07}{0.036}

Z = -1.39

Z = -1.39 has a pvalue of 0.0823

So

P(p < .02) = 0.0823

2. Determine P(p > .15).

This is 1 subtracted by the pvalue of Z when X = 0.15. So

Z = \frac{X - \mu}{s}

Z = \frac{0.15 - 0.07}{0.036}

Z = 2.22

Z = 2.22 has a pvalue of 0.9868

1 - 0.9868 = 0.0132

So

P(p > .15) = 0.0132

3. Determine P(.05 < p < .09).

This is the pvalue of Z when X = 0.09 subtracted by the pvalue of Z when X = 0.05. So

X = 0.09

Z = \frac{X - \mu}{s}

Z = \frac{0.09 - 0.07}{0.036}

Z = 0.55

Z = 0.55 has a pvalue of 0.7088

X = 0.05

Z = \frac{X - \mu}{s}

Z = \frac{0.05 - 0.07}{0.036}

Z = -0.55

Z = -0.55 has a pvalue of 0.2912

0.7088 - 0.2912 = 0.4176. So

P(.05 < p < .09) = 0.4176

3 0
3 years ago
It’s identifying and writing expressions <br> Please help.!
belka [17]

Answer:

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Hope this helps

Step-by-step explanation:

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Sveta_85 [38]

Answer:

b=18

Step-by-step explanation:

1/3b -3=3

1/3b-3+3=3+3

1/3b= 6

isolate b

1/3 *3 b= 6 *3

b=18

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It is 2.5 I did the test
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