(3*j)-8
I thinkkkk... I’m positive tho
Hello from MrBillDoesMath!
Answer:
4( x + 1.5)^2 + 0
Discussion:
4x^2 + 12x + 9 = => factor "4" from first 2 terms
4 (x^2 + 3x) + 9 = => complete the square, add\subtract (1.5)^2
4(x^2 + 3x + (1.5)^2) - 4 (1.5)^2 + 9 =
4 ( x + 1.5)^2 + ( 9 - 4(1.5)^2) = => as (1.5)^2 = 2.25
4 ( x + 1.5)^2 + ( 9 - 4(2.25)) = => as 4 ( 2.25) = 9
4 ( x+ 1.5)^2 + 0
Thank you,
MrB
Use Math..way. Put in equation, hit solve, will give u val. for N
Answer:
x = ±i√2
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality<u>
</u>
<u>Algebra II</u>
Imaginary root <em>i</em>
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
5x² - 2 = -12
<u>Step 2: Solve for </u><em><u>x</u></em>
- [Addition Property of Equality] Add 2 on both sides: 5x² = -10
- [Division Property of Equality] Divide 5 on both sides: x² = -2
- [Equality Property] Square root both sides: x = ±√-2
- Rewrite: x = ±√-1 · √2
- Simplify: x = ±i√2
