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lord [1]
3 years ago
10

What is the least common denominator of1/3 and 1/5

Mathematics
2 answers:
ella [17]3 years ago
8 0
The LCD is 1/15 and 3/15.
gizmo_the_mogwai [7]3 years ago
8 0
The number that results from calculating the lowest common multiple of the denominators of those same fractions is called the lowest common denominator of two or more fractions.
 1/3 and 1/5
 The minimum common denominator is:
 (3) * (5) = 15
 Answer:
 the least common denominator is:
 15
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898÷91,596 what is the answer
Dmitrij [34]

Answer:

For 100, your answer will be 102; For 898, your answer will be x; 100*x = 102*898 ... 102/x = 100/898 or x/102 = 898/100; x = 898*102/100 = 91596/100 = 915.96.

Hope this helps ∝

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7 0
3 years ago
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Mei subscribed to a magazine at a rate of $24 for 12 issues. When she placed her order, Mei used a coupon that added 3 free bonu
lord [1]

Answer:

initial cost per issue=$2

after subscription cost per issue=$1.6.

Step-by-step explanation:

Initially , Mei subscribed $24 for 12 issues for a magazine .When Mei used a coupen then 3 free bonus issues added to her subcsription .Therefore we can see the coupon reduces the cost per issue of Mei's subscription. Before use of coupon the cost of each issue is $2 and after added 3 more issue of coupon then the cost per issue is $1.6

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3 years ago
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What is the cost of buying 5 kg of cheese worth<br> $9.00 per kg?
topjm [15]
$45

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6 0
3 years ago
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Radioactive Waste The rate at which radioactive waste is entering the atmosphere at time t is decreasing and is given by Pe^-kt,
Dmitry_Shevchenko [17]

Answer:

\displaystyle{\int^{\infty}_0 {50e^{-0.04t}}\, dt}=1250

Step-by-step explanation:

Given:

T =\displaystyle{\int^{\infty}_0 {Pe^{-kt}} \, dt}

where,

T = total amount of waste

P = 50, the initial rate

k = 0.04

t = time

T =\displaystyle{\int^{\infty}_0 {50e^{-0.04t}} \, dt}

now we need to solve this integral!

T =\displaystyle{50\int^{\infty}_0 {e^{-0.04t}} \, dt}

T = \left|50\left(\dfrac{e^{-0.04t}}{-0.04}\right)\right|^{\infty}_0

T = \left|-1250e^{-0.04t}\right|^{\infty}_0

T = (-1250e^{-0.04(\infty)})-(-1250e^{-0.04(0)})

when any number has a power of negative infinity it is 0. because: a^-{\infty} = \dfrac{1}{a^{\infty}} = \dfrac{1}{\infty} = 0, like something being divided by a very large number!

T = (-1250(0))-(-1250e^0)

T = 1250

this is the total amount of waste

6 0
3 years ago
Easy<br> a) -2,-5.-8.-11,...
aleksklad [387]

Step-by-step explanation:

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