Answer:
Not sure sorry,but can you please help me on the following:
Step-by-step explanation:
Length of a rectangle is 5 cm longer than the width. Four squares are constructed outside the rectangle such that each of the squares share one side with the rectangle. The total area of the constructed figure is 120 cm2. What is the perimeter of the rectangle?
The mixture is 1 cup of vinegar to 1 gallon of water.
Since 1 gallon is 16 cups, it could also be
1 cup of vinegar to 16 cups of water.
If we had 80 fluid ounces of water, we'd have to change the water to 5 fluid ounces to keep the mixture the same. (It's still 1 part vinegar, 16 parts water)
Answer:
h ≈ 9.9 cm
Step-by-step explanation:
By applying tangent rule for the given angle in the given right triangle,
tan(51°) = 
tan(51°) =
h = 8 × tan(51°)
h = 9.879
h ≈ 9.9 cm
Therefore, measure of side 'h' is 9.9 cm.
The question is incomplete. Here is the complete question:
Mr.yueng graded his students math quizzes students came up with four different answers when solving the equation x3=22. Which answers is correct.
(A) 
(B) ![\sqrt[3]{22}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B22%7D%20)
(C)
(D) 
Answer:
(B) ![\sqrt[3]{22}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B22%7D)
Step-by-step explanation:
Given:
The equation to solve is given as:

Here, the left hand side of the equation has a variable 'x' in exponent form. So, in order to solve for 'x', we have to eliminate the exponent.
For removing the exponent, we have to take cubic root on both the sides. As we know that,
![\sqrt[n]{x^n} =x](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%5En%7D%20%3Dx)
So, taking cubic root on both the sides, we get
![\sqrt[3]{x^3}=\sqrt[3]{22}\\\\x=\sqrt[3]{22}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E3%7D%3D%5Csqrt%5B3%5D%7B22%7D%5C%5C%5C%5Cx%3D%5Csqrt%5B3%5D%7B22%7D)
Therefore, the second student has written the correct answer and hence the correct option is (B).
Tnemos el sisema de ecuaciones:

Podemos resolverlo por eliminación sumando ambas ecuaciones y eliminando y. Asi podemos resolver para x:

Ahora podemos resolver para y con cualquiera de las dos ecuaciones:

Respuesta: x=-3, y=0