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Tcecarenko [31]
3 years ago
10

The sum of three numbers is 125. The first number is 7 more than the first. The third number is 4 times the second.What are the

numbers
Mathematics
1 answer:
xenn [34]3 years ago
4 0

Answer:

15, 22, 88

Step-by-step explanation:

I assume you mean the second number is 7 more than the first.  Write the system of equations:

x + y + z = 125

y = x + 7

z = 4y

Substitute the third equation into the first.

x + y + 4y = 125

x + 5y = 125

Substitute the second equation.

x + 5(x + 7) = 125

6x + 35 = 125

6x = 90

x = 15

Solve for the other variables.

y = 22

z = 88

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Answer:

Not sure sorry,but can you please help me on the following:

Step-by-step explanation:

Length of a rectangle is 5 cm longer than the width. Four squares are constructed outside the rectangle such that each of the squares share one side with the rectangle. The total area of the constructed figure is 120 cm2. What is the perimeter of the rectangle?

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The mixture is 1 cup of vinegar to 1 gallon of water.
Since 1 gallon is 16 cups, it could also be
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The diagram shows a right-angled triangle.
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Answer:

h ≈ 9.9 cm

Step-by-step explanation:

By applying tangent rule for the given angle in the given right triangle,

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h = 8 × tan(51°)

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Mr.yueng graded his students math quizzes students came up with four different answers when solving the equation x3=22. Which an
alex41 [277]

The question is incomplete. Here is the complete question:

Mr.yueng graded his students math quizzes students came up with four different answers when solving the equation x3=22. Which answers is correct.

(A) \frac{22}{3}

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(C) \pm \sqrt[3]{22}

(D) \sqrt{22}

Answer:

(B) \sqrt[3]{22}

Step-by-step explanation:

Given:

The equation to solve is given as:

x^3=22

Here, the left hand side of the equation has a variable 'x' in exponent form. So, in order to solve for 'x', we have to eliminate the exponent.

For removing the exponent, we have to take cubic root on both the sides. As we know that,

\sqrt[n]{x^n} =x

So, taking cubic root on both the sides, we get

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3 years ago
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Sistema de ecuaciones.5x+2y=-152x-2y=-6
Zolol [24]

Tnemos el sisema de ecuaciones:

\begin{gathered} 5x+2y=-15 \\ 2x-2y=-6 \end{gathered}

Podemos resolverlo por eliminación sumando ambas ecuaciones y eliminando y. Asi podemos resolver para x:

\begin{gathered} (5x+2y)+(2x-2y)=(-15)+(-6) \\ 7x+0y=-21 \\ x=-\frac{21}{7} \\ x=-3 \end{gathered}

Ahora podemos resolver para y con cualquiera de las dos ecuaciones:

\begin{gathered} 2x-2y=-6 \\ 2\cdot(-3)-2y=-6 \\ -6-2y=-6 \\ -2y=-6+6 \\ -2y=0 \\ y=0 \end{gathered}

Respuesta: x=-3, y=0

7 0
1 year ago
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