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agasfer [191]
3 years ago
13

HELP PLEASE

Mathematics
1 answer:
Lapatulllka [165]3 years ago
7 0
\bf \qquad \qquad \textit{sum of a finite arithmetic sequence}\\\\
S_n=\cfrac{n}{2}(a_1+a_n)~ 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
a_n=n^{th}~value\\
----------\\
a_1=30\\
S_n=-210
\end{cases}
\implies
-210=\cfrac{n}{2}(30+a_n)\\\\\\ -420=n(30+a_n)\implies -420=30n+na_n
\\\\\\
-420-30n=na_n\implies \boxed{\cfrac{-420-30n}{n}=a_n}\\\\
-------------------------------

\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
a_1=30\\
d=-4
\end{cases}
\\\\\\
a_n=30+(n-1)(-4)\implies a_n=30-4n+4
\\\\\\
\boxed{a_n=34-4n}\\\\
-------------------------------

\bf \stackrel{a_n}{34-4n}~~=~~\stackrel{a_n}{\cfrac{-420-30n}{n}}\implies 34n-4n^2=-420-30n
\\\\\\
0=4n^2-64n-420\implies 0=4(n^2-16n-105)
\\\\\\
0=n^2-16n-105\implies 0=(n-21)(n+5)\implies n=
\begin{cases}
\boxed{21}\\
-5
\end{cases}

since the term is just a term unit in the sequence, it cannot be a negative value, thus is not -5.
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