16% percent of the students paid MORE than Jane.
The mean(μ) of money spent on textbooks is 500
The standard deviation(σ) of money spent on textbooks is 50
Money paid by Jane for her books is $550
We will use this formula,
Ζ=x-μ/σ
To find: the percentage of students paid MORE than Jane for the textbooks
=?
Solution:
≤
=
Ζ≤
=1-P(Ζ≤ 1)
=1-0.8413
=0.1587
≈16%
Therefore, 16% percent (approx) of the students paid MORE than Jane.
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Answer: Box A, 2.777
=======================================================
Explanation:
When using a calculator or long division, you should find that
7/9 = 0.7777...
where the 7s go on forever
So we can say that 7/9 = 0.777 approximately. You could argue that the last '7' would round up to an '8' and we could say 7/9 = 0.778; however, I'll stick to the first value so that it matches with the answer.
Since 7/9 = 0.777, this means 2 & 7/9 = 2 + 7/9 = 2 + 0.777 = 2.777 which is box A.
1 furlong = 1/8 miles
6 furlongs = x miles
xmiles = 1/8(6 furlongs)
Xmiles= 3/4 miles
Which is 0.75 miles
Please give my answer the brainliest
Answer:


Step-by-step explanation:
Given


Required
Which completes the model
Let the remaining probability be x.
Such that:

Make x the subject

So, we have:

Solve



This mean that the remaining model must add up to 1/2


Take LCM


This is false because: 


Take LCM



This is true


Take LCM



This is true
Other options are also false