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2 years ago

Round 80,547.645 to the place of the underlined digit with the 5 after the decimal underlined

Mathematics

1 answer:

evablogger [386]2 years ago

8 0

Ok buddy sorry i didn’t answer your question but i did not get coke

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Convert the polar equation to rectangular coordinates. (Use variables x and y as needed.)

Alinara [238K]

The standard conversion toolbox:
x=rcos(θ)
y=rsin(θ)

Here r=7csc(θ)
so
x=7csc(θ)*cos(θ)=7cos(θ)/sin(θ)=7cot(θ)
y=7csc(θ)*sin(θ)=7sin(θ)/sin(θ) = 7
therefore the rectangular coordinates are (7cot(θ), 7)

8 0

3 years ago

X + 2 – z; use x = 6, and z = 2

grin007 [14]

Answer:

Step-by-step explanation:

x + 2 - z
If x = 6 and z = 2 then : 6 + 2 -2
6 +2 is 8 - 2 is six
answer is 6

4 0

3 years ago

I need to Match each equation that represents each situation.

almond37 [142]

Step-by-step explanation:

this is quite easy, when you use just common sense and identify the right numbers and variable names.

they is nothing special needed, you don't even need to create the equations yourself.

$4.99 per pound. buys b pounds and pays $14.95.

14.95 = 4.99 × b

$4.99 per pound. buys b pounds and pays c.

this is exactly the same as before, just that this time the total amount is not given as a constant but as a variable.

c = 4.99 × b

d dollars per pound. buys b pounds and pays t.

the same as the 2 cases before, just now everything is a variable. no more constants, but otherwise the completely same structure and method.

t = d × b

earned $275, which is $45 more than Noah ("n").

$275 = n + $45

earned m dollars, which is $45 more than Noah ("n").

m = n + $45

earned m dollars, which is y dollars more than Noah (we are asked that Noah's earnings are now called "v").

here your teacher made a mistake.

sure, the only remaining answer is

v = m + y

but it is not correct. given the names of the prime and associated variables the correct answer would be

m = v + y or v = m - y

7 0

1 year ago

Find the Maclaurin series for f(x) using the definition of a Maclaurin series. [Assume that f has a power series expansion. Do n

aliya0001 [1]

Answer:

$f(x)=\sum_{n=1}^{\infty}(-1)^{(n-1)}2^{n}\dfrac{x^n}{n}$

Step-by-step explanation:

The Maclaurin series of a function f(x) is the Taylor series of the function of the series around zero which is given by

$f(x)=f(0)+f^{\prime}(0)x+f^{\prime \prime}(0)\dfrac{x^2}{2!}+ ...+f^{(n)}(0)\dfrac{x^n}{n!}+...$

We first compute the n-th derivative of $f(x)=\ln(1+2x)$ , note that

$f^{\prime}(x)= 2 \cdot (1+2x)^{-1}\\f^{\prime \prime}(x)= 2^2\cdot (-1) \cdot (1+2x)^{-2}\\f^{\prime \prime}(x)= 2^3\cdot (-1)^2\cdot 2 \cdot (1+2x)^{-3}\\...\\\\f^{n}(x)= 2^n\cdot (-1)^{(n-1)}\cdot (n-1)! \cdot (1+2x)^{-n}\\$

Now, if we compute the n-th derivative at 0 we get

$f(0)=\ln(1+2\cdot 0)=\ln(1)=0\\\\f^{\prime}(0)=2 \cdot 1 =2\\\\f^{(2)}(0)=2^{2}\cdot(-1)\\\\f^{(3)}(0)=2^{3}\cdot (-1)^2\cdot 2\\\\...\\\\f^{(n)}(0)=2^n\cdot(-1)^{(n-1)}\cdot (n-1)!$

and so the Maclaurin series for f(x)=ln(1+2x) is given by

$f(x)=0+2x-2^2\dfrac{x^2}{2!}+2^3\cdot 2! \dfrac{x^3}{3!}+...+(-1)^{(n-1)}(n-1)!\cdot 2^n\dfrac{x^n}{n!}+...\\\\= 0 + 2x -2^2 \dfrac{x^2}{2!}+2^3\dfrac{x^3}{3!}+...+(-1)^{(n-1)}2^{n}\dfrac{x^n}{n}+...\\\\=\sum_{n=1}^{\infty}(-1)^{(n-1)}2^n\dfrac{x^n}{n}$

3 0

3 years ago

One team c 82.5% of the football players weigh more then 200 pounds if 40 men are on the team how many weigh more then 200 pound

valentinak56 [21]

The answer is 33 because 40*0.825 or 40*82.5% is 33 men.

7 0

3 years ago