Sean has 36 ft of fence to put around a rectangular flower bed how long and how wide will the

What is the approximate area of the circle shown below 9.4 cm

aivan3 [116]

Answer:

Step-by-step explanation:

A= πr²

A= 22/7 multiply by the radius.

Divide 9.4cm by 2.

Whatever you get is your answer. Now take the formula I have shown you above. Whatever you get is your answer.

6 0

3 years ago

Please answer these questions! will mark brainlist!

timofeeve [1]

1st photo....

Yes

Explanation

All when divided becomes 1/3 , so it is proportional...

Pls mark brainliest

2nd photo....

Yes

Explaination

Also when divided becomes 1/3... Same proportional

7 0

3 years ago

Read 2 more answers

Help pleaseeeeeeeeeeeee

eduard

Step-by-step explanation:

17.0 there you go I hope this helped

4 0

3 years ago

Read 2 more answers

HELP URGENT BRAINLIEST

nadya68 [22]

Given:

LMN is an equilateral triangle.

LM = LN = MN = 12 cm

To find:

The height of the triangle h.

Solution:

In a right angle triangle,

$\sin \theta=\dfrac{Opposite}{Hypotenuse}$

$\sin (60^\circ)=\dfrac{h}{12}$

$\dfrac{\sqrt{3}}{2}=\dfrac{h}{12}$

Multiply both sides by 12.

$\dfrac{\sqrt{3}}{2}\times 12=\dfrac{h}{12}\times 12$

$6\sqrt{3}=h$

Therefore, the height of the triangle is $6\sqrt{3}$ cm.

3 0

3 years ago

Consider a system with one component that is subject to failure, and suppose that we have 115 copies of the component. Suppose f

castortr0y [4]

Answer:

Step-by-step explanation:

From the given information:

the mean $(\mu) = 115 \times 20$

= 2300

Standard deviation = $20 \times \sqrt{115}$

Standard deviation (SD) = 214.4761

TO find:

a) $P(x > 3500)= P(Z > \dfrac{3500-\mu}{214.4761})$

$P(x > 3500)= P(Z > \dfrac{3500-2300}{214.4761})$

$P(x > 3500)= P(Z > \dfrac{1200}{214.4761})$

$P(x > 3500)= P(Z >5.595)$

From the Z-table, since 5.595 is > 3.999

$P(x > 3500)=1-0.9999$

P(x > 3500) = 0.0001

b)

Here, the replacement time for the mean $(\mu) = \dfrac{0+0.5}{2}$

= 0.25

Replacement time for the Standard deviation $\sigma = \dfrac{0.5-0}{\sqrt{12}}$

$\sigma = 0.1443$

For 115 component, the mean time = (115 × 20)+(114×0.25)

= 2300 + 28.5

= 2328.5

Standard deviation = $\sqrt{(115\times 20^2) +(114\times (0.1443)^2)}$

= $\sqrt{(115\times 400) +(114\times 0.02082249}$

= $\sqrt{(46000) +2.37376386}$

= $\sqrt{(46000) +(2.37376386)}$

= $\sqrt{46002.374}$

= 214.482

Now; the required probability:

$P(x > 4125) = P(Z > \dfrac{4125- 2328.5}{214.482})$

$P(x > 4125) = P(Z > \dfrac{1796.5}{214.482})$

$P(x > 4125) = P(Z >8.376)$

$P(x > 4125) =1- P(Z$

From the Z-table, since 8.376 is > 3.999

P(x > 4125) = 1 - 0.9999

P(x > 4125) = 0.0001

7 0

3 years ago