The chance for landing less than 4 is 1/2 chance.
So the circle is really easy to graph. All you have to do is put a point at (1,2). Then another four points: 8 to the right of the center, 8 up from center, 8 left from center, and 8 down from center. Then contect the outer points.
The parabola is a little harder. So I can't see the equation very well, but I'm going to assume your vertix is correct. So put a point at (0,0).
The focus is 4 up from the center (0,4). The directrix is the same distance from the vertix as the focus, in the opposite direction. But it'll be horizontal or vertical line. This one I, believe, is y=-4.
So the parabola will open away from the directrix and towards the focus. You need two more points to graph this.
If I remember correctly, the other two points should be 2 x the focus/directrix distance. So 8, but even with the focus. Your other two points would be (0,12) (0, -4)
Then just connect the vertix to these two points. The only thing I need to double check is the distance betwen the focus with the two points.
Answer:
x
<
−
3
Step-by-step explanation:
Y−6=3<span>(x−3<span>)
</span></span>Explanation:<span><span>the equation of a line in point-slope form</span> is.<span>∙xy−<span>y1</span>=m<span>(x−<span>x1</span>)</span></span><span>where m is the slope and <span>(<span>x1</span>,<span>y1</span>)</span> a point on the line</span><span>to calculate the slope m use the gradient formula</span><span>∙xm=<span><span><span>y2</span>−<span>y1</span></span><span><span>x2</span>−<span>x1</span></span></span></span><span>let <span>(<span>x1</span>,<span>y1</span>)</span>=<span>(3,6)</span> and <span>(<span>x2</span>,<span>y2</span>)</span>=<span>(0,−3)</span></span><span>⇒m=<span><span>−3−6</span><span>0−3</span></span>=<span><span>−9</span><span>−3</span></span>=3</span>use either of the 2 given points for the point on the line<span>using <span>(<span>x1</span>,<span>y1</span>)</span>=<span>(3,6)</span> then</span><span>y−6=3<span>(x−3)</span>←<span>in point-slope form</span></span></span>
