Question

In the length of each leg of an isosceles triangle is 13 and the base is 24, the length of the altitude to the base is

Answer 1

Answer:

altitude = 5

Step-by-step explanation:

Look at the picture.

Use the Pythagorean theorem:

$a^2+12^2=13^2$

$a^2+144=169$               subtract 144 from both sides

$a^2=25\to a=\sqrt{25}\\\\a=5$