Answer: " m = zC / (C − z) " .
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Explanation:
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Given: 1/C + 1/m = 1/z ; Solve for "m".
Subtract "1/C" from each side of the equation:
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1/C + 1/m − 1/C = 1/z − 1/C ;
to get: 1/m = 1/z − 1/C ;
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Now, multiply the ENTIRE EQUATION (both sides); by "(mzC"); to get ride of the fractions:
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mzC {1/m = 1/z − 1/C} ;
to get: zC = mC − mz ;
Factor out an "m" on the "right-hand side" of the equation:
zC = m(C − z) ; Divide EACH side of the equation by "(C − z)" ; to isolate "m" on one side of the equation;
zC / (C − z) = m(C − z) / m ; to get: 24/8 = 3 24
zC/ (C − z) = m ; ↔ m = zC/ (C − z) .
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Answer:
-5
Step-by-step explanation:
or, f(x) = -x^2+10x+16
or, f(7) = (-7)^2+10*-7+16 (-7*-7=49)
=49-70+16
=65-70
=-5
I think it is 30.48 because i looked it up
Answer:
(x - 9) + (x + 3)
Step-by-step explanation:
To get the correct answer when factoring the numbers must add up to be the middle variable and multiply together to be the ending original number.
Answer:
The weight of cat is <u>14 pounds</u> and the weight of kitten is <u>4 pounds</u>.
Step-by-step explanation:
Given:
Callie has a new kitten. It can weigh 3 pounds less than half the weight of Callie‘s cat. Together the cat and kitten weigh 18 pounds.
Now, to find the weight of each animal:
Let the cat's weight be 
And the kitten weight = 
Total weight of cat and kitten = 18 pounds.
Now, to set an equation to get the weight of each animal:




<em>Multiplying both sides by 2 we get:</em>
<em />
<em />
<em>Adding both sides by 6 we get:</em>
<em />
<em />
<em>Dividing both sides by 3 we get:</em>
<em />
<em />
<em>The weight of cat = 14 pounds.</em>
Substituting the value of
to get the kitten's weight:

<em>The kitten's weight = 4 pounds.</em>
Therefore, the weight of cat is 14 pounds and the weight of kitten is 4 pounds.