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vaieri [72.5K]
3 years ago
13

The outdoor temperature was 60 degrees at midnight. The temperature went down 3 degrees each hour for the next 4 hours. What was

the temperature at 4 AM
Mathematics
1 answer:
12345 [234]3 years ago
8 0
3 x 4(hours) = 12
60 - 12 = 48
At 4am the temperature was 48 degrees
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What is the answer for this problem?
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3 years ago
In the regular octagon, the numeric value of the area of the shaded region is twice more than the numeric value of the length of
s2008m [1.1K]

Answer:

A =  (2+√8)L² - 2L, where L is the length of AB

Step-by-step explanation:

Lets call L the length of one side. The octagon can be divided in 8 triangles composed by the vertices of the octagon and the center. The base of each triangle has length L and the height is L/2 + M, with M such that 2M² = L². This is because the center of the octagon is located at middle height of the center sides. You can reach that height by 'travelling' from the bottom side throught one slanted side (which is the hypotenuse of a isosceles rectangle triangle of height M) and then you travel throught a center side half its length. Thus, h = L/2 + L/√2.

The area of each triangle of the octagon therefore is, as a result, h*L/2 = L²/4 + L²/2√2

Hence, the area of the octagon is 8*(L²/4 + L²/2√2) = (2+√8)L². The unshaded region area can be computed by taking this number and substract to it the value of 2L, which is the area of the shaded region (The double of the length of a side)

As a result,

A =  (2+√8)L² - 2L

8 0
3 years ago
One of the factor of x² +3x+2 is x+1 then the other factor is …..​
azamat

Hi there!

\large\boxed{(x + 2)}

x² + 3x + 2

We know that x + 1 is a factor, so:

We must find another number that adds up to 3 when added to 1 and multiplies into 2 with 1. We get:

x + 2

(x + 1)(x + 2)

6 0
3 years ago
I need help with this work problem please. I put the picture of problem thank you.
Deffense [45]
Your work looks good, the ages will be 

\bf \stackrel{\textit{20 to 30}}{25\%}~~+~~\stackrel{\textit{31 to 40}}{22\%}~~+~~\stackrel{\textit{41 to 50}}{13\%}\implies 60\%
\\\\\\
\textit{60\% of 125000}\implies \cfrac{60}{100}\cdot 125000\implies 75000
5 0
3 years ago
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