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musickatia [10]
3 years ago
14

1.2,3,7.5,18.75 which formula can used to describe the sequence?

Mathematics
1 answer:
n200080 [17]3 years ago
8 0

Answer:

a_n=1.2 \cdot 2.5^{n-1}

Step-by-step explanation:

The first step is to realize that this is a geometric sequence, where each next term in the sequence is 2.5 times larger than the previous. You can confirm this by the fact that 3=1.2*2.5, 7.5=3*2.5, and 18.75=7.5*2.5. Now, you can write the formula, where n is where the number is in the sequence, and a is the number itself. Since 1.2 is the first term in the sequence and the rate of expansion is 2.5, the formula is:

a_n=1.2 \cdot 2.5^{n-1}

Hope this helps!

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Using the binomial distribution, it is found that there is a 0.0108 = 1.08% probability of the coin landing tails up at least nine times.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • The coin is fair, hence p = 0.5.
  • The coin is tossed 10 times, hence n = 10.

The probability that is lands tails up at least nine times is given by:

P(X \geq 9) = P(X = 9) + P(X = 10)

In which:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 9) = C_{10,9}.(0.5)^{9}.(0.5)^{1} = 0.0098

P(X = 10) = C_{10,10}.(0.5)^{10}.(0.5)^{0} = 0.001

Hence:

P(X \geq 9) = P(X = 9) + P(X = 10) = 0.0098 + 0.001 = 0.0108

0.0108 = 1.08% probability of the coin landing tails up at least nine times.

More can be learned about the binomial distribution at brainly.com/question/24863377

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She has twice as much money invested at 8% as she does in 7%.

She has three times as much at 9% as she has at 7%.

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Suppose x be the amount invested at 7%. Then,

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The amount invested at 9% = 3x

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Dividing both sides by 50, we get

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