<span>The function that would best model the situation given above is polynomial.
That is because the vertical motion is uniformly accelerated, with acceleration equal to g ≈ 9.8 m/s^2 downward.
Therefore, the distance is modeled by d = Vo*t + g*t^2 / 2.
So, as you see it is second grade polynomial.
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I'm pretty sure this is correct, but it depends on how ur teacher wants it to be written like.
The answer would be 7.225.
<u>Given</u>:
Given that TUV is a right triangle.
The measure of ∠T is 16°
The length of VT is 4.9 feet.
We need to determine the length of TU.
<u>Length of TU:</u>
The length of TU can be determined using the trigonometric ratio.
Thus, we have;

where
, adj = TV and hyp = TU
Thus, we get;

Simplifying, we get;



Rounding off to the nearest tenth, we get;

Thus, the length of TU is 5.1 feet.
Answer: x= 2 4/5 or 2.8
y= 4
Step-by-step explanation:
hope this helps