<span>The number of x-intercepts that appear on the graph of the function
</span>f(x)=(x-6)^2(x+2)^2 is two (2): x=6 (multiplicity 2) and x=-2 (multiplicity 2)
Solution
x-intercepts:
f(x)=0→(x-6)^2 (x+2)^2 =0
Using that: If a . b =0→a=0 or b=0; with a=(x-6)^2 and b=(x+2)^2
(x-6)^2=0
Solving for x. Square root both sides of the equation:
sqrt[ (x-6)^2] = sqrt(0)→x-6=0
Adding 6 both sides of the equation:
x-6+6=0+6→x=6 Multiplicity 2
(x+2)^2=0
Solving for x. Square root both sides of the equation:
sqrt[ (x+2)^2] = sqrt(0)→x+2=0
Subtracting 2 both sides of the equation:
x+2-2=0-2→x=-2 Multiplicity 2
I’m pretty sure the answer is A I hope that helps :)
1. 21j-26+4j=21+6-2j
2. 25j-26=27-2j
3. 27j=53
4. j=53/27
hope this helps!!
Answer:
23
Step-by-step explanation:
Okay so since with the penny it's 1/5 that means there's only one penny and 5 other coins and 100% is 5 then 80% will be 4 so your answer is 80% hope this helps
