If the exterior angle is 120 degrees, you subtract 120 degrees from 360 degrees (the two angles form a circle) and get 240 degrees.
This is not a possible angle for a triangle because the angles in a triangle always add up to 180 degrees. Also, angles in triangles can’t be more than 180 degrees
Answer: OPTION C.
Step-by-step explanation:
<h3>
The complete exercise is: "Air pressure may be represented as a function of height (in meters) above the surface of the Earth, as shown below:</h3><h3>
</h3><h3>
In this function
is the air pressure at the surface of the earth, and
is the height above the surface of the Earth, measured in meters. At what height will the air pressure equal 50% of the air pressure at the surface of the Earth"</h3><h3>
</h3>
Given the following function:

In order to calculate at what height the air pressure will be equal 50% of the air pressure at the surface of the Earth, you can follow these steps:
1. You need to substitute
into the function:

2. Finally, you must solve for
.
Remember the following property of logarithms:

Then, you get this result:

The answer is the 2nd choice
Step-by-step explanation:
from the point -10 to -4 thre is a difference of 6 uints . Base 6
from the x-axis to furthest point,
there is a difference of 6 units. Height 6