Answer:
D: {(-5, -4, 2, 2, 5)}
R: {(-6, 3, 4, 1, 5)}
The relation is NOT a function.
Step-by-step explanation:
By definition:
A relation is any set of ordered pairs, which can be thought of as (input, output).
A function is a <em><u>relation</u></em> in which no two ordered pairs have the same first component (domain/input/x value) and different second components (range/output/y value).
Looking at the given points in your graph, and in listing down the domain and range, we can infer that the relation is not a function because there is an x-value (2) that has two corresponding y-values: (2, 4) (2, 1).
Another way to tell if a given set of points in a graph represents a function by doing the "Vertical line test." The graph of an equation represents y as a function of x if and only if no vertical line intersects the graph more than once. Looking at the attached image, I drew a vertical line over points (2, 4) (2, 1). The vertical line intersects the two points, which fails the vertical line test. This is an indication that the given relation is not a function.
Answer: 192
Step-by-step explanation: 24 • 8
Answer: C) 16
We know that the x or y axis side is 2 and 6
If we double the number to find the perimeter:
2 - 4
6 - 12
—-
16
Therefore the answer is 16
After paying 4 tolls, Tony will have 4×$1.25 = $5.00 less change in his car. At that point, he will have $1 in change. The appropriate choice is
graph of line going through (0, 6) and (4,1)
Answer:
no
Step-by-step explanation:
The prices are inconsistent, so there is no unique price that can be set for either an apple or an orange that will give the total prices indicated.
__
The first relation can be written as ...
$10 = 4A +4O
$10 = 4(A +O) . . . . factor out 4
$2.50 = A +O . . . . divide by 4
The second relation can be written as ...
$12 = 6A +6O
$12 = 6(A +O) . . . . factor out 6
$2 = A +O . . . . . . . divide by 6
These two relations give different prices for 1 apple and 1 orange. There is no price that can be set for either fruit that will give this result.
No unique prices can be assigned.