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miv72 [106K]
3 years ago
12

Which expression is equivalent to...

Mathematics
1 answer:
torisob [31]3 years ago
7 0

Answer:

x^{\frac{2}{7} } y^{-\frac{3}{5} } \\  i.e answer A.

Step-by-step explanation:

This question involves knowing the following power/exponent rule:

\sqrt[n]{x^m} = x^\frac{m}{n} \\\\so \sqrt[7]{x^2} = x^\frac{2}{7} \\\\and  \\\\ \sqrt[5]{y^3} = y^\frac{3}{5} \\

Next, when a power is on the bottom of a fraction, if we want to move it to the top, this makes the power become negative.

so the y-term, when moved to the top of the fraction, becomes:

y^{-\frac{3}{5} } \\

So the answer is: x^{\frac{2}{7} } y^{-\frac{3}{5} } \\

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MariettaO [177]
Then it would be 600 
4 0
3 years ago
Write a rule for the linear function in the table.
Ira Lisetskai [31]

Answer:

f(x) = 4 - x

Step-by-step explanation:

'f(x) = blah-blah' is the same as saying 'y = blah-blah', except it is also telling you that the x-y relationship is a function.

I notice that for each case, x + y = 4, so    y = 4 - x

Or in 'function' terminology,                       f(x) = 4 - x

5 0
3 years ago
The equation of line CD is y = -2x - 2. What is the equation of a line parallel to line CD in slope-intercept form that contains
castortr0y [4]

Answer:

y=-2x+13

Step-by-step explanation:

Slope-intercept form of a line is y=mx+b where m is slope and b is y-intercept.

The slope of y=-2x-2 is -2 since m=-2.

A line that is parallel to the given line is going to have the same slope.

So we already know the equation we are looking for should be in the form y=-2x+b.

We just to need to find b.

We can use the given point on our line do that.

5=-2(4)+b

5=-8+b

8+5=b

13=b

So the equation is y=-2x+13.

6 0
3 years ago
Read 2 more answers
PLEASE HELP FAST!!!!!
ddd [48]
Prime factorization is 2*2*2*2*2*2
2 sets of triples can be made
None
x^13
4sets of triples one left over
y^15
5sets of triples
7 0
3 years ago
2)
seropon [69]

Answer:

35.98 is the answer idk if thats what u be lookin for tho

Step-by-step explanation:

5 0
3 years ago
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