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3 years ago

I need help ASAP with this?

Mathematics

1 answer:

luda_lava [24]3 years ago

8 0

Answer:

x = ±½

Though P is shown in the third quadrant so probably expecting x = -½

Step-by-step explanation:

Unit circle so radius is 1

x = √(1² - (½√3)²) = √(1 - 0.75) = √0.25 = ±½

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Answer:

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Step-by-step explanation:

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3 years ago

The length of the rectangle is 4cm less than its width . what are the dimensions of the rectangle if its area is 140

melomori [17]

Let the width of the rectangle be x
Then length =x-4
Area=x(x-4)=140
x²-4x=140
x²-4x-140=0
x²-14x+10x-140=0
x(x-14)+10(x-14)=0
(x-14)(x+10)=0
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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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kondaur [170]

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3 years ago

The frequency table represents the job status of a number of high school students. A 4-column table with 3 rows titled job statu

lys-0071 [83]

Answer:

$\begin{array}{cccc}{} & {Looking\ for\ job} & {Not\ looking} & {Total} & {Employed} & {0.24} & {0.28} & {0.27} & {Not\ Employed} & {0.76} & {0.72} & {0.73}& {Total} & {1} & {1} & {1} \ \end{array}$

Step-by-step explanation:

The question is not properly formatted (see attachment for the frequency table and the options)

Required

The conditional relative frequency table by column

We have:

$\begin{array}{cccc}{} & {Looking\ for\ job} & {Not\ looking} & {Total} & {Employed} & {12} & {28} & {40} & {Not\ Employed} & {38} & {72} & {110}& {Total} & {50} & {100} & {150} \ \end{array}$

To get the conditional frequency by column, we simply divide each cell by the corresponding total value (on the last row)

So, we have:

$\begin{array}{cccc}{} & {Looking\ for\ job} & {Not\ looking} & {Total} & {Employed} & {12/50} & {28/100} & {40/150} & {Not\ Employed} & {38/50} & {72/100} & {110/150}& {Total} & {50/50} & {100/100} & {150/150} \ \end{array}$

$\begin{array}{cccc}{} & {Looking\ for\ job} & {Not\ looking} & {Total} & {Employed} & {0.24} & {0.28} & {0.27} & {Not\ Employed} & {0.76} & {0.72} & {0.73}& {Total} & {1} & {1} & {1} \ \end{array}$

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3 years ago