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kupik [55]
3 years ago
9

There are 238 juniors at a high school The ratio of boys to girls in the junior class is 3:4. How many juniors are girls?

Mathematics
2 answers:
Tatiana [17]3 years ago
8 0
Answer: 136

Explanation:

Find the girls in junior class:

238 x 4/7 = 136
LiRa [457]3 years ago
3 0

Answer:

59.5

Step-by-step explanation:

I know there cannot be half a human running around the school, and I don't exactly remember if you round up or down, but there are a total of 238 juniors in the school. you divide 238 by 4. the girls represent one fourth of the juniors, and the boys represent three fourths. thank you, please mark brainliest!

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3x + 5 = x - 3
dusya [7]

Answer:

x = -4

Step-by-step explanation:

3x + 5 = x - 3

Subtract x from each side

3x+5-x = x-3-x

2x+5 = -3

Subtract 5 from each side

2x+5-5 = -3-5

2x = -8

Divide each side by 2

2x/2 = -8/2

x = -4

7 0
3 years ago
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Given the following functions f(x) and g(x), solve (f ⋅ g)(3) and select the correct answer below:
Ksenya-84 [330]
I believe you may have the order incorrect. If we were looking at g(f(x)) the answer would be 47. We would get this by sticking the 3 in for x in f(x) and solving, which would give us 48. We would then stick that answer in for x in the g(x), giving us 47. 

In its current order the answer would be 28. 
6 0
3 years ago
El valor de 2 – 3(5 + 2)(5 – 8) es
Margarita [4]

Answer:

65

Step-by-step explanation:

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= 2 - 3 ( 7 ) ( -3 )

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6 0
2 years ago
What is the simplified expression for,
Nostrana [21]

Here are a few rules you need to know for this equation:

  • Multiplying exponents of the same base: x^m\times x^n=x^{m+n}
  • Dividing exponents of the same base: \frac{x^m}{x^n}=x^{m-n}
  • Turning a negative exponent to a positive one: x^{-m}=\frac{1}{x^m};\frac{1}{x^{-m}}=x^m

So this is our algebraic expression: \frac{3^{-4}\times 2^3\times 3^2}{2^4\times 3^{-3}}

Firstly, multiply 3^-4 and 3^2: \frac{3^{-4+2}\times 2^3}{2^4\times 3^{-3}}=\frac{3^{-2}\times 2^3}{2^4\times 3^{-3}}

Next, divide:

\frac{3^{-2}\times 2^3}{2^4\times 3^{-3}}=3^{-2-(-3)}2^{3-4}=3^12^{-1}

Next, turn the negative exponent into a positive one: 3^12^{-1}= \frac{3}{2}

<u>Your final answer is 3/2, or 1.5.</u>

6 0
3 years ago
How do you solve powers of powers in advanced algebra
Anna35 [415]
Ex: 2^2^2

Basically, the base is multiplied by the first power however large the number. Then the new base is multiplied by the second power to get an even larger number.
Say you have a question that asks for the power of the power of 2. Or 2^2^2.

You would do the equation 2^2 first, and end up with 4. But since you have another power, you would have the answer as 4^2. Which would then equal 16. But another equation that is similar is: 2^2^2 = 2^4
The two equations would still get the same answer, but would look entirely different.
7 0
3 years ago
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