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crimeas [40]
2 years ago
9

there are 1176 students in central high school. there are 50 more girls than boys. how many boys are there.

Mathematics
1 answer:
bagirrra123 [75]2 years ago
8 0
563 boys and 613 girls
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Which of the following best describes the set of all numbers of the form a+bi where a and b are any real numbers and i equals sq
Andrei [34K]
<h3>Answer: B) Complex numbers</h3>

Complex numbers are always in the form a+bi with 'a' and 'b' as real numbers.

If b = 0 and 'a' is nonzero, then a+bi = a+0i = a which is strictly a real number

If a = 0 and b is nonzero, then a+bi = 0+bi = bi indicating that the number is now purely imaginary

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3 years ago
Write down two prime numbers that have a sum of 32​
DaniilM [7]

19 and 13 can be the numbers

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5 0
2 years ago
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Find the percent of the area under the density curve where x is more than 3. <br>​
Gekata [30.6K]

Answer:

The percent of the area under the density curve where x is more that 3 is 25 %.

Step-by-step explanation:

Since the density curve is a linear function, the area under the curve can be calculated by the geometric formula for a triangle, defined by the following expression:

A = \frac{1}{2}\cdot (x_{f} - x_{o})\cdot  (y_{f}-y_{o}) (1)

Where:

A - Area, in square units.

x_{f} - x_{o} - Base of the triangle, in units.

y_{f} - y_{o} - Height of the triangle, in units.

The percent of the area is the ratio of triangle areas under the density curve multiplied by 100 per cent, that is:

x = \frac{\frac{1}{2}\cdot (5-3)\cdot (0.25) }{\frac{1}{2}\cdot (5-1)\cdot (0.5) }\times 100\,\%

x = 25\,\%

The percent of the area under the density curve where x is more that 3 is 25 %.

7 0
3 years ago
(I will give brainliest to whoever can answer this correctly)
BartSMP [9]

Answer:

1) area =25

perimeter= 24

2) area=49

perimeter=30

4 0
2 years ago
(Middle school math) I just need to know the probabilities for letter a. Thank you.
lisov135 [29]

Answer:

use a tree diagram to get a visual representation over it then calculate you're probability.

4 0
3 years ago
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