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Karolina [17]
3 years ago
15

On a field trip there were 5 girls for every 8 boys. How many girls attended the 130 student trip?

Mathematics
2 answers:
arlik [135]3 years ago
6 0
50 girls attended the trip. ( 80 boy + 50 girls = 130 total students) You just multiply both by 10.
Lerok [7]3 years ago
5 0
The answer is 50 girls attented the trip
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Solve each equation for y (get into slope-intercept/y=mx + b form):
Gwar [14]

Answer:

Step-by-step explanation:

In order to do this we need to isolate y by performing the inverse operations on the other values like so...

a)   10x + 5y = 20   ... subtract 10x on both sides

     5y = 20 - 10x    ... divide both sides by 5

       y = 4 - 2x   ... we can move the 2x to the right to make it into y = mx + b

       y = -2x + 4

b)   3x - 2y = 10 + 4x   ... subtract 3x on both sides

      -2y = 10 + x    ... divide both sides by -2

       y = -5 - 0.5x ... move -0.5 to the left so it matches y = mx + b

      y = -0.5x - 5

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3 years ago
A grocer's shop sells carrots, onions and cucumbers.
kolezko [41]

Answer: 3:4

Step-by-step explanation:

7 0
2 years ago
Use an associative property to write an equivalent expression
Angelina_Jolie [31]

Answer:

6y+3xy

Step-by-step explanation:

You can combine the y's together to get this answer

3 0
3 years ago
Comparing Leaking Pool Problem
Blababa [14]

Answer:

<em>Pool 1 leaks faster than pool 2.</em>

Step-by-step explanation:

<u>Rates of change</u>

The rate of change (ROC) is a measure that compares two quantities, usually to know how fast one variable changes in time.

We are given two rates of change for two pools that are leaking. The first one loses 2/3 gallon in 15 minutes, and the other loses 3/4 gallon in 20 minutes.

To compare them, we are required to express time in hours. Recall one hour has 60 minutes, or equivalently, one minute has 1/60 hours. Converting both times, we have:

15 minutes = 15/60 = 1/4 hours

20 minutes = 20/60 = 1/3 hours

Now compute both rates of change:

Pool 1:

\displaystyle ROC_1=\frac{2/3}{1/4}=\frac{8}{3}\approx 2.67\ gal/h

Pool 2:

\displaystyle ROC_2=\frac{3/4}{1/3}=\frac{9}{4}= 2.25\ gal/h

Comparing both ratios, it's clear pool 1 leaks faster than pool 2.

8 0
3 years ago
The mean annual income for people in a certain city is 37 thousand dollars, with a standard deviation of 28 thousand dollars. A
Aloiza [94]

Answer:

P( 31 < \bar X< 41)

And we can ue the z score formula given by:

z= \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And using this formula we got for the limits:

z = \frac{31-37}{\frac{28}{\sqrt{50}}}= -1.515

z = \frac{41-37}{\frac{28}{\sqrt{50}}}= 1.01

So we want to find this probability:

P(-1.515

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the annual income of a population, and for this case we know the following info:

\mu=37 and \sigma=28  and we are omitting the zeros from the thousand to simplify calculations

We select a sample size of n=50>30.

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we want to find this probability:

P( 31 < \bar X< 41)

And we can ue the z score formula given by:

z= \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And using this formula we got for the limits:

z = \frac{31-37}{\frac{28}{\sqrt{50}}}= -1.515

z = \frac{41-37}{\frac{28}{\sqrt{50}}}= 1.01

So we want to find this probability:

P(-1.515

4 0
3 years ago
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