Comparing Leaking Pool Problem
1 answer:
Answer:
<em>Pool 1 leaks faster than pool 2.</em>
Step-by-step explanation:
<u>Rates of change</u>
The rate of change (ROC) is a measure that compares two quantities, usually to know how fast one variable changes in time.
We are given two rates of change for two pools that are leaking. The first one loses 2/3 gallon in 15 minutes, and the other loses 3/4 gallon in 20 minutes.
To compare them, we are required to express time in hours. Recall one hour has 60 minutes, or equivalently, one minute has 1/60 hours. Converting both times, we have:
15 minutes = 15/60 = 1/4 hours
20 minutes = 20/60 = 1/3 hours
Now compute both rates of change:
Pool 1:
Pool 2:
Comparing both ratios, it's clear pool 1 leaks faster than pool 2.
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Answer:
<em>a. The system of equations that models the situation is....</em>
<em> </em>
<em>b. The solution to the system: x = 2 and y = 4 </em>
<em>The amount of 80/20 mixture is 2 pounds and the amount of 50/50 mixture is 4 pounds.</em>
Step-by-step explanation:
Suppose, the amount of 80/20 mixture is pounds and the amount of 50/50 mixture is
pounds.
So, the amount of peanuts in 80/20 mixture pound and the amount of almonds in 80/20 mixture
pound.
And the amount of peanuts in 50/50 mixture pound and the amount of almonds in 50/50 mixture
pound.
Now, Sarah would like to make a 6 pounds nut mixture that is 60% peanuts and 40% almonds.
So, the amount of peanuts in that mixture pounds
and the amount of almonds in that mixture pounds.
So, the system of equations will be.........
Subtracting equation (2) from equation (1), we will get.....
Now, plugging this into equation (1), we will get......
So, the amount of 80/20 mixture is 2 pounds and the amount of 50/50 mixture is 4 pounds.
Answer:
B. (0.61)
Step-by-step explanation:
Well, first I created venn diagram to help separate my work, then I subtracted .22 from each "probability sections" then I added them up to get .61
Work explains a lot.
Hope it helped. :)
