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borishaifa [10]
3 years ago
11

The general equation is y=ax squared+bx+c based off true and false

Mathematics
1 answer:
andrew11 [14]3 years ago
3 0
Trueirh3hv3v3ueidheg3
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50 POINTS!!! DO NOT ANSWER JUST FOR THE POINTS!!! IF YOU DO, ALL OF YOUR EARNED POINTS WILL BE TAKEN~~~~~~~~~~~~~~~
amm1812
A) [-7,-4] U [4,7]; B) [-4,-1]; C) [1,4]


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Find the value of x in 5rasised to power x=125
mestny [16]
5^3=125
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Which of the following statements is correct Athe product of 3/4 and 7/8 is less than 7/8 B the product of 1/3 and 9/10 is less
dedylja [7]

Identify the slope, m. This can be done by calculating the slope between two known points of the line using the slope formula.

Find the y-intercept. This can be done by substituting the slope and the coordinates of a point (x, y) on the line in the slope-intercept formula and then solve for b.

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3 years ago
Morgan likes to put the same number of trophies on each shelf of her trophy case. She has a total of 75 trophies, and each shelf
ololo11 [35]

Answer:

A=5

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divide both sides by 15

5 0
3 years ago
Write a rule to describe the function shown. x y −6 −4 −3 −2 0 0 3 2 y equals start fraction two over three end fraction x y equ
sertanlavr [38]

Answer:

y=\frac{2}{3} x (y equals start fraction two over three end fraction x)

Step-by-step explanation:

Lest's organize the table values of our function first:

x    y

-6  -4

-3  -2

0   0

3   2

The simplest kind of of function is a linear function of the form y=mx+b where m is the slope and b is the y-intercept. Let's us check if our function is a linear one finding its equation and checking that all points are in the line.

The first step to find a linear equation is find the slope of the line; to do it, we are using the slope formula:

m=\frac{y_2-y_1}{x_2-x_1}

where

m is the slope of the line

(x_1,y_1) are the coordinates of the first point

(x_2,y_2) are the coordinates of the second point

We know from our table that the first and second points are (-6, -4) and (-3, -2) respectively, so x_1=-6, y_1=-4, x_2=-3, and y_2=-2.

Replacing values:

m=\frac{y_2-y_1}{x_2-x_1}

m=\frac{-2-(-4)}{-3-(-6)}

m=\frac{-2+4}{-3+6)}

m=\frac{2}{3)}

Now that we have the slope of our line we can use the point slope formula to complete our linear function:

y-y_1=m(x-x_1)

where

m is the slope

(x_1,y_1) are the coordinates of the first point

Replacing values:

y-y_1=m(x-x_1)

y-(-4)=\frac{2}{3)}(x-(-6))

y+4=\frac{2}{3)}(x+6)

y+4=\frac{2}{3} x+4

y=\frac{2}{3} x+4-4

y=\frac{2}{3} x

Now, to check if our function is valid, we can either check if each point satisfies the rule y=\frac{2}{3} x, or we can graph it and check if each lies is in the graph.

Let's check both:

We already know that points (-6, -4) and (-3, -2) satisfy the rule (after all, those were the point we used to came out with the rule in the first place), so we just need to check the points (0, 0) and (3, 2)

- For (0, 0):

y=\frac{2}{3} x

0=\frac{2}{3}(0)

0=0

The point satisfies the rule.

- For (3, 2):

y=\frac{2}{3} x

2=\frac{2}{3} (3)

2=2

The point satisfies the rule.

Since all the points of our table satisfies the rule y=\frac{2}{3} x, we can conclude that the rule describing the function shown is y=\frac{2}{3} x.

4 0
3 years ago
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