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babymother [125]
3 years ago
10

EVALUATE !!!! ILL GIVE YOU BRAINLIST HAVE TO GET IT RIGHT !!!!

Mathematics
1 answer:
elena-s [515]3 years ago
8 0

Answer:

<h2>12</h2>

Step-by-step explanation:

nxy\div m\\\\n =3/4\\x =8\\y =6\\m=3\\\\\frac{3}{4} \times 8 \times 6 \div 3\\\\\mathrm{Divide\:the\:numbers:}\:6\div \:3=2\\=\frac{3}{4}\times \:8\times \:2\\\\\mathrm{Convert\:element\:to\:fraction}:\quad \:8=\frac{8}{1}\\=2\times \frac{3}{4}\times \frac{8}{1}\\\\\mathrm{Convert\:element\:to\:fraction}:\quad \:2=\frac{2}{1}\\=\frac{3}{4}\times \frac{8}{1}\times \frac{2}{1}\\\\Multiply\:fractions\\=\frac{3\times \:8\times \:2}{4\times \:1\times \:1}\\\\=\frac{48}{4}\\\\Simplify\\=12

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Shawna lives in an apartment 9 4/5 miles from the hospital where she works. Her brother rents a room in a house 7 2/5 miles from
tamaranim1 [39]

Answer:

2 2/5 miles

Step-by-step explanation:

6 0
2 years ago
Please help:<br> In Δ ABC, sin A=88, sin B=42, and a =17, find the length of b.
iren2701 [21]

Answer:

Step-by-step explanation:

Use the law of sines.

\frac{sin A}{a} = \frac{sin B}{b} \\

Plug values in.

\frac{sin88}{17} = \frac{sin42}{b}\\

Cross multiply.

bsin88 = 17sin42\\b = 11.38

Hope that helps.

6 0
3 years ago
Read 2 more answers
A rectangle has a perimeter of 196 meters and a length of 50 meters.What is the width of the rectangle? Explain.
matrenka [14]
Answer: 48 meters

we already know that one side is 50 m, so since it's a
rectangle you can multiply 50 by 2 which gives you 100. Know you have two sides left (which would be the same number) . You can do it easy and subtract 196 and 100 which gives you 96. Then, divide 96 by 2 and you get 48.

---- check: do 48(2)+50(2) it will give you 196


HOPE THIS HELPED

3 0
3 years ago
Someone please help me with this lol… have no idea what I’m doing
Sholpan [36]

Given:

\cos \theta =\dfrac{3}{5}

\sin \theta

To find:

The quadrant of the terminal side of \theta and find the value of \sin\theta.

Solution:

We know that,

In Quadrant I, all trigonometric ratios are positive.

In Quadrant II: Only sin and cosec are positive.

In Quadrant III: Only tan and cot are positive.

In Quadrant IV: Only cos and sec are positive.

It is given that,

\cos \theta =\dfrac{3}{5}

\sin \theta

Here cos is positive and sine is negative. So, \theta must be lies in Quadrant IV.

We know that,

\sin^2\theta +\cos^2\theta =1

\sin^2\theta=1-\cos^2\theta

\sin \theta=\pm \sqrt{1-\cos^2\theta}

It is only negative because \theta lies in Quadrant IV. So,

\sin \theta=-\sqrt{1-\cos^2\theta}

After substituting \cos \theta =\dfrac{3}{5}, we get

\sin \theta=-\sqrt{1-(\dfrac{3}{5})^2}

\sin \theta=-\sqrt{1-\dfrac{9}{25}}

\sin \theta=-\sqrt{\dfrac{25-9}{25}}

\sin \theta=-\sqrt{\dfrac{16}{25}}

\sin \theta=-\dfrac{4}{5}

Therefore, the correct option is B.

6 0
2 years ago
What's the answer and how?
vredina [299]
Hey can you take another pic
5 0
3 years ago
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