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Nata [24]
2 years ago
15

In a second grade class containing 13 girls and 9 boys, 2 students are selected at random to give out the math papers. What is t

he probability that the second student chosen is a boy, given that the first one was a girl?
Mathematics
2 answers:
Finger [1]2 years ago
8 0
13/22 x 9/21 = 0.25                                               
Rashid [163]2 years ago
4 0

Answer:

42.86% probability that the second student chosen is a boy, given that the first one was a girl.

Step-by-step explanation:

Initially, there are 22 students, of which 13 are girls and 9 are boys.

The first student chosen was a girl, so now there are 21 students, of which 12 are girls and 9 are boys.

What is the probability that the second student chosen is a boy, given that the first one was a girl?

There are 21 students, of which 9 are boys. So there is a 3/7 = 0.4286 = 42.86% probability that the second student chosen is a boy, given that the first one was a girl.

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What is the value of StartFraction 6 Over x EndFraction + 2x2, when x = 3?
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<h2>The value of StartFraction 6 Over x EndFraction + 2x2, when x = 3 is 20.</h2>

Explanation:

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Describe how the variability of the distribution changes as the sample size increases. As the sample size increases, the variabi
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Answer:

As the sample size increases, the variability decreases.

Step-by-step explanation:

Variability is the measure of actual entries from mean.  The less the deviations the less would be the variance.

For a sample  of size n, we have by central limit theorem the mean of sample follows a normal distribution for random samples of large size.

X bar will have std deviation as \frac{s}{\sqrt{n} }

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7 0
3 years ago
Whats the difference between 24 and -14.
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Solve the given system of equations2y=x+93x-6y=-15
attashe74 [19]

Answer:

No solutions

Explanation:

The given system of equations is

2y = x + 9

3x - 6y = -15

To solve the system, we first need to solve the first equation for x, so

2y = x + 9

2y - 9 = x + 9 - 9

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Then, replace x = 2y - 9 on the second equation

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5 0
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