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o-na [289]
3 years ago
14

These four steps are important when setting a goal, but they are in the wrong order.what is the correct order of steps from star

t to finish
Chemistry
2 answers:
ankoles [38]3 years ago
5 0
The first step is to establish a goal and write it down. This adds commitment and you are declaring your intentions.
The second step is write down your daily plan of action. A plan without action is as useless if you had never written the goal at all. 
The third step is to share your goal with someone who will hold you accountable. They can share your victories , failures, and provide encouragement.
The final step is to act on that plan. You must take action now that you have all the tools. 

ddd [48]3 years ago
3 0
A. Define an honest, attainable, and clear goal                 
D. Determine a schedule and outline your steps     
B. Assess ways to problem-solve obstacles     
C. <span>Self-monitor your activities</span>          
You might be interested in
1.00 M CaCl2 Density = 1.07 g/mL
Lesechka [4]

Explanation:

Molarity of solution = 1.00 M = 1.00 mol/L

In 1 L of solution 1.00 moles of calcium chloride is present.

Mass of solute or calcium chloride = m

m = 1 mol\times 111 g/mol = 111 g

Mass of solution = M

Volume of solution = V = 1L = 1000 mL

Density of solution , d= 1.07 g/mL

M=d\times V=1.07 g/mL\times 1000 mL=1,070 g

1) The value of %(m/M):

\frac{m}{M}\times 100=\frac{111 g}{1,070 g}\times 100=10.37\%

2) The value of %(m/V):

\frac{m}{V}\times 100=\frac{111 g}{1000 L}\times 100=11.1\%

Molality = \frac{\text{Moles of compound }}{\text{mass of solvent in kg}}

Normality=\frac{\text{Moles of compound }}{n\times \text{volume of solution in L}}

n = Equivalent mass

n = \frac{\text{molar mass of ion}}{\text{charge on an ion}}

3) Normality of calcium ions:

Moles of calcium ion = 1 mol (1 CaCl_2 mole has 1 mole of calcium ion)

n=\frac{40 g/mol}{2}=20

=\frac{1 mol}{20 g/mol\times 1L}=0.050 N

4) Normality of chlorine ions:

Moles of chlorine ion = 2 mol (1 CaCl_2 mole has 2 mole of chlorine ion)

n=\frac{35.5 g/mol}{1}=35.5

=\frac{2 mol}{35.5 g/mol\times 1L}=0.056 N

Moles of calcium chloride = 1.00 mol

Mass of solvent =  Mass of solution - mass of solute

= 1,070 g - 111 g = 959  g = 0.959 kg ( 1 g =0.001 kg)

5) Molality of the solution :

\frac{1 mol}{0.959 kg}=1.043 mol/kg

Moles of calcium chloride = n_1=1mol

Mass of solvent = 959 g

Moles of water = n_2=\frac{959 g}{18 g/mol}=53.28 mol

Mass of solvent = 959 g

6) Mole fraction of calcium chloride =

\chi_1=\frac{n_1}{n_1+n_2}=\frac{1mol}{1 mol+53.28 mol}=0.01842

7) Mole fraction of water =

\chi_2=\frac{n_2}{n_1+n_2}=\frac{53.28 mol}{1mol+53.28 mol}=0.9816

8) Mass of solution = m'

Volume of the solution= v = 100 mL

Density of solution = d = 1.07 g/mL

m'=d\times v=1.07 g/ml\times 100 g= 107 g

Mass of 100 mL of this solution 107 grams of solution.

9) Volume of solution = V = 100 mL

Mass of solution = M'' = 107 g

Mass of solute = m

The value of %(m/V) of solution = 11.1%

11.1\%=\frac{m}{100 mL}\times 100

m = 11.1 g

Mass of solvent = M''- m = 107 g -11.1 g = 95.9 g

95.9 grams of water was present in 100 mL of given solution.

3 0
3 years ago
An old sample of concentrated sulfuric acid to be used in the laboratory is approximately 98.1 percent h2so4 by mass. calculate
Airida [17]
Basis: 100 mL solution

From the given density, we calculate for the mass of the solution.

                        density  = mass / volume
                        mass = density x volume

                       mass = (1.83 g/mL) x (100 mL) = 183 grams

Then, we calculate for the mass H2SO4 given the percentage.
                   
                      mass of H2SO4 = (183 grams) x (0.981) = 179.523 grams

Calculate for the number of moles of H2SO4,
                  moles H2SO4 = (179.523 grams) / (98.079 g/mol)
                        moles H2SO4 = 1.83 moles

Molarity:
                     M = moles H2SO4 / volume solution (in L)
                         = 1.83 moles / (0.1L ) = 18.3 M

Molality:
                     m = moles of H2SO4 / kg of solvent
                        = 1.83 moles / (183 g)(1-0.983)(1 kg/ 1000 g) = 588.24 m
8 0
3 years ago
Is mass conserved when 40 g of sodium hydroxide undergoes a chemical change during an interaction with 37g of hydrogen chloride?
DENIUS [597]

Answer:

Mass is conserverd

Explanation:

Any chemical reaction must follow the law of conservation of mass. Meaning that mass cannot be created nor destroyed. Since all chemical reactions must follow this law, no matter what reaction happens, mass is conserved.

7 0
3 years ago
Standardization of a Borax solution (Na2B4O7). You are given a 1.044 M solution of H2SO4. It takes 2.63 mL of this H2SO4 to reac
strojnjashka [21]

The question is incomplete, the complete question is:

Standardization of a Borax solution (Na2B4O7). A student titrates a 20.00 mL sample of an aqueous borax solution with 1.044 M H2SO4. It takes 2.63 mL of acid to reach the equivalence point. Knowing it takes 1 H2SO4 to neutralize 2 Na2B4O7, what was the concentration of this Borax solution?

<u>Answer: </u>The concentration of borax solution is 0.069 M.

<u>Explanation:</u>

To calculate the concentration of borax solution, the formula used is:

n_1C_1V_1=n_2C_2V_2 ....(1)

where,

n_1, C_1\text{ and }V_1 are the n-factor, concentration and volume of sulfuric acid

n_2,C_2\text{ and }V_2 are the n-factor, concentration and volume of borax solution.

We are given:

n_1=1\\C_1=1.044M\\V_1=2.63mL\\n_2=2\\C_2=?M\\V_2=20mL

Putting values in equation 1, we get:

1\times 1.044\times 2.63=2\times C_2\times 20\\\\C_2=\frac{1\times 1.044\times 2.63}{2\times 20}\\\\C_2=0.069M

Hence, the concentration of borax solution is 0.069 M.

8 0
3 years ago
Prior to the Industrial Revolution, the majority of the population in England consisted of the light colored variation. The dark
Bad White [126]

Dark colored moths survived better in the Industrial Revolution because their dark color helped them camouflage in soot. When the industrial revolution ended there wasn't as much soot, so the light colored moths now had a better chance of survival.

6 0
3 years ago
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