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geniusboy [140]
3 years ago
7

Ozone (O 3) is made of three atoms of oxygen. It is _

Chemistry
2 answers:
marshall27 [118]3 years ago
4 0
A molecule! Hope this helps :)
kykrilka [37]3 years ago
3 0
An element I think maybe
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Answer:

With what?

Explanation:

4 0
3 years ago
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Classify methanal according to the position of the c=o group
seraphim [82]

Answer :  Methanal also known as Formaldehyde CH_{2}O is a chemical Aldehyde which contain ( -CHO) group.

Explanation :

In organic chemistry, a carbonyl group is a functional group which contain a carbon atom double-bonded to an oxygen atom i.e, ( C=O).

     If carbonyl group is present in a compound then it can be a carboxylic (RCOOH), aldehyde (RCHO), ketone (RCOR'), ester ((RCOOR') or amide (RCONR'R") group.

Here are some functional groups naming according to the<em> IUPAC</em> rules and image also attached,

Carboxylic acid   →    (RCOOH)    →    ( name end in 'OIC ACID' )

Aldehyde             →    (RCOH)       →    ( name end in 'AL' )

Ketone                 →    (RCOR')       →    ( name end in 'ONE' )

Ester                     →    (RCOOR')    →    ( name end in 'ATE' )

Amide                   →    (RCONR'R") →    ( name end in 'AMIDE' )

In an aldehyde, atleast one hydrogen atom must be attached to the carbonyl carbon. For an aldehyde, remove ( -e) from alkane name and add ( -al) at the end of the compound.

Methanal is the IUPAC name for Formaldehyde.


3 0
3 years ago
NItrogen in air reacts at high temperature to form NO2 according to the reaction:
Rina8888 [55]

Answer:

The correct answer is option E.

Explanation:

Structures for the reactants and products are given in an aimage ;

Number of double bonds in oxygen gas molecule = 1

Number of double bonds in nitro dioxide gas molecule = 1

Number of single bond in in nitro dioxide gas molecule = 1

Number of triple bonds in nitrogen gas molecule = 1

N_2+2O_2\rightarrow 2NO_2,\Delta H=?

\Delta H=[2 mol\times \Delta H_{f,NO_2}]-[1 mol\times \Delta H_{f,N_2}-2 mol\times \Delta H_{f,O_2}]

\Delta H_{f,NO_2}=33.18 kJ/mol

\Delta H_{f,N_2}=0 (pure element)

\Delta H_{f,O_2}=0 (pure element )

\Delta H=2 mol\times 33.18 kJ/mol=66.36kJ=15.86 kcal

The enthalpy of the given reaction is 15.86 kcal.

6 0
4 years ago
Each of the four liquids had the same volume. Why didn’t
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When the equal molar amounts of of both the acid and the base were reacts, what happened in the reaction?
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It is going to be reaction of neutralization, and water and salt will be formed. If acid and base are strong, the reaction of the solution should become neutral.
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