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3 years ago

Which must be the same when comparing 1 mol of oxygen gas, O2, with 1 mol of carbon monoxide gas, CO?

Chemistry

2 answers:

gayaneshka [121]3 years ago

7 0

Answer: C. The Number of Molecules

Explanation:

I just took the test.

Llana [10]3 years ago

5 0

A mole is a rather unusual unit of measurement. It is defined by a specific number of particles, molecules, atoms, or any other unit.
That number happens to be 6.022×10²³.
When we talk about a mole of water, then, we refer to 6.022×10²³ molecules of water.

Comparing 1 mole of 02 with 1 mole of CO:
This means means that both quantities will have the same number of molecules. The answer is C.

It may be tempting to select D, since it relates to the number of atoms rather than mass or volume, and moles are related to this idea. However, keep in mind that one mole of O2 will actually have twice as much oxygen atoms as one mole of CO, since there are two oxygen atoms per O2 molecule and only 1 oxygen atom per CO molecule.

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You mix 145 grams of water with 200 grams of ethanol to make a solution. What is the solute and what is the solvent?

hodyreva [135]

The greater amount is the solvent and the lesser amount is the solute.

Hence ethanol(200g) which is the greater amount is the solvent here.

And water (145g) which is lesser is the solute here.

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2 years ago

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kirza4 [7]

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6 0

3 years ago

Convert 135 Meters to kilometers

tamaranim1 [39]

Answer:

0.135 km

Explanation:

1 km = 1000 meters

7 0

2 years ago

4.81*10^24 atoms of lithium

enyata [817]

Answer:

Mass = 55.52 g

Explanation:

Given data:

Number of atoms of Li = 4.81×10²⁴ atom

Number of grams = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen

For Li:

4.81×10²⁴ atom × 1 mol / 6.022 × 10²³ atom

8 moles

Mass in gram:

Mass = number of moles × molar mass

Mass = 8 mol × 6.94 g/mol

Mass = 55.52 g

4 0

3 years ago

For the following reaction, 6.94 grams of water are mixed with excess sulfur dioxide . Assume that the percent yield of sulfurou

Alexxx [7]

<h3>Answer:</h3>

#a. Theoretical yield = 31.6 g

#b. Actual yield = 25.72 g

<h3>Explanation:</h3>

The equation for the reaction between sulfur dioxide and water to form sulfurous acid is given by the equation;

SO₂(g) + H₂O(l) → H₂SO₃(aq)

The percent yield of H₂SO₃ is 81.4%

Mass of water that reacted is 6.94 g

#a. To get the theoretical yield of H₂SO₃ we need to follow the following steps

Step 1: Calculate the moles of water

Molar mass of water = 18.02 g/mol

Mass of water = 6.94 g

But, moles = Mass/molar mass

Moles of water = 6.94 g ÷ 18.02 g/mol

= 0.385 mol

Step 2: Calculate moles of H₂SO₃

From the equation, the mole ratio of water to H₂SO₃ is 1 : 1

Therefore, moles of water = moles of H₂SO₃

Hence, moles of H₂SO₃ = 0.385 mol

Step 3: Theoretical mass of H₂SO₃

Mass = moles × Molar mass

Molar mass of H₂SO₃ = 82.08 g/mol

Number of moles of H₂SO₃ = 0.385 mol

Therefore;

Theoretical mass of H₂SO₃ = 0.385 mol × 82.08 g/mol

= 31.60 g

Thus, the theoretical yield of H₂SO₃ is 31.6 g

<h3>#b. Calculating the actual yield</h3>

We need to calculate the actual yield

Percent yield of H₂SO₃ is 81.4%

Theoretical yield is 31.60 g

But; Percent yield = (Actual yield/theoretical yield)×100

Therefore;

Actual yield = Percent yield × theoretical yield)÷ 100

= (81.4 % × 31.6) ÷ 100

= 25.72 g

The percent yield of H₂SO₃ is 25.72 g

6 0

2 years ago