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3 years ago

Which must be the same when comparing 1 mol of oxygen gas, O2, with 1 mol of carbon monoxide gas, CO?

Chemistry

2 answers:

gayaneshka [121]3 years ago

7 0

Answer: C. The Number of Molecules

Explanation:

I just took the test.

Llana [10]3 years ago

5 0

A mole is a rather unusual unit of measurement. It is defined by a specific number of particles, molecules, atoms, or any other unit.
That number happens to be 6.022×10²³.
When we talk about a mole of water, then, we refer to 6.022×10²³ molecules of water.

Comparing 1 mole of 02 with 1 mole of CO:
This means means that both quantities will have the same number of molecules. The answer is C.

It may be tempting to select D, since it relates to the number of atoms rather than mass or volume, and moles are related to this idea. However, keep in mind that one mole of O2 will actually have twice as much oxygen atoms as one mole of CO, since there are two oxygen atoms per O2 molecule and only 1 oxygen atom per CO molecule.

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Question 2(Multiple Choice Worth 4 points)

densk [106]

Answer:

B. Construct a hypothesis

6 0

2 years ago

Read 2 more answers

Nitrogen was heated from 17°C to 37°C. The original volume of nitrogen was 8.5 L. Find the new volume in liters assuming P and n

Nata [24]

Answer:

The new volume of the gas is 9.086 liters.

Explanation:

Let suppose that nitrogen has a behavior of ideal gas, the equation of state for ideal gases is:

$P\cdot V = n \cdot R_{u}\cdot T$ (1)

Where:

$P$ - Pressure, measured in atmospheres.

$V$ - Volumen, measured in liters.

$n$ - Molar amount, measured in moles.

$T$ - Temperature, measured in Kelvin.

$R_{u}$ - Ideal gas constant, measured in atmosphere-liters per mole-Kelvin.

If pressure and molar amount of the gas remain constant, then we construct the following relationship:

$\frac{T_{1}}{V_{1}} = \frac{T_{2}}{V_{2}}$ (2)

If we know that $T_{1} = 290.15\,K$ , $P_{1} = 8.5\,L$ and $T_{2} = 310.15\,K$ , then the new volume of the gas is:

$V_{2} = \left(\frac{T_{2}}{T_{1}}\right)\cdot V_{1}$

$V_{2} = \left(\frac{310.15\,K}{290.15\,K} \right)\cdot (8.5\,L)$

$V_{2} = 9.086\,L$

The new volume of the gas is 9.086 liters.

7 0

3 years ago

When 0.250 moles of a gas is placed in a container at 298K, it exerts a pressure of 93kPa. What is the volume of the container?

Drupady [299]

I think is c , I’m not sure

4 0

2 years ago

When measuring the volume of the marble, why is it better to use the 25-mL graduated cylinder than the 100-mL graduated cylinder

AnnZ [28]

Answer:

$\boxed {\tt A \ marble \ is \ small}$

Explanation:

A marble is not a very large object, so a smaller graduated cylinder is a better choice. A 100 milliliter graduated cylinder is not needed to measure the volume of a small marble, so a 25 milliliter graduated cylinder is the best option.

5 0

3 years ago

What properties of matter are intensive independent of their size

Paha777 [63]

Answer:

temperature, refractive index, density, and hardness of an object

Explanation:

it is a bulk property, meaning that it is a physical property of a system that does not depend on the system size or the amount of material in the system

8 0

2 years ago