5y+3x=13/2y=-5x+57/10 steps
1 answer:
Express the system in standard form:
{3 x + 5 y = 13/2 | (equation 1)
{5 x + y = 57/10 | (equation 2)
Swap equation 1 with equation 2:
{5 x + y = 57/10 | (equation 1)
{3 x + 5 y = 13/2 | (equation 2)
Subtract 3/5 × (equation 1) from equation 2:
{5 x + y = 57/10 | (equation 1)
{0 x+(22 y)/5 = 77/25 | (equation 2)
Multiply equation 1 by 10:
{50 x + 10 y = 57 | (equation 1)
{0 x+(22 y)/5 = 77/25 | (equation 2)
Multiply equation 2 by 25/11:
{50 x + 10 y = 57 | (equation 1)
{0 x+10 y = 7 | (equation 2)
Divide equation 2 by 10:
{50 x + 10 y = 57 | (equation 1)
{0 x+y = 7/10 | (equation 2)
Subtract 10 × (equation 2) from equation 1:
{50 x+0 y = 50 | (equation 1)
{0 x+y = 7/10 | (equation 2)
Divide equation 1 by 50:
{x+0 y = 1 | (equation 1)
{0 x+y = 7/10 | (equation 2)
Collect results:
Answer: {x = 1
{y = 7/10
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Step-by-step explanation:
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