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BaLLatris [955]

2 years ago

12

find two positive consecutive odd intergers such that the square of the larger integer is one less than twice the square of the

smaller integer

1 answer:

Tju [1.3M]2 years ago

3 0

Answer:

The integers are 5 and 7.

Step-by-step explanation:

see image.

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Can someone help me please

dmitriy555 [2]

Answer:

Step-by-step explanation:

The rule with like bases is that when you multiply them you add their exponents.

$m^4*m^1=m^5$

Therefore, our final simplification is

$4m^5n^7$

7 0

3 years ago

Read 2 more answers

What is the solution to this system of equations<br>(5z +y=2<br>( 47 +y=5

prisoha [69]

Answer:

Z = 8.8 Y = - 42

Step-by-step explanation:

Y = 2 - 5Z

Y = 5 - 47

2 - 5Z = 5 - 47

- 5Z = - 44

5Z = 44

Z = 8.8

Y = 2 - 5 (8.8)

Y = 2 - 44

Y = - 41

Y = 5 - 47

Y = - 42

5 0

3 years ago

What percent of 77.5 is 28.52 ?

Fantom [35]

I would say 36.8
But I am it sure

8 0

3 years ago

A circle has a diameter of 4 inches. Which statement about the area and circumference of the circle is true?

hoa [83]

Only the second one
when diameter is 4 r=2
so 2pi*2=2²*pi the first is circumference the second area

7 0

3 years ago

4xy + 10yᒾ<br> Tui mún hỏii

slavikrds [6]

Answer:

4xy+10y²=2y(2x+5y)

Hope it helps!!!

3 0

2 years ago