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sattari [20]
4 years ago
6

1.)3(5-8)+(-12•2) 2.)15 / (2+3)-(6-8) ( /= division)

Mathematics
1 answer:
gizmo_the_mogwai [7]4 years ago
5 0
1) -33
2) 5

hope this helps!!
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See attachment. Please give step by step solution. Thank you
Dmitry_Shevchenko [17]

Answer:

x=19

Step-by-step explanation:

cross multiply

(−3)(+5)(3+5)=(−3)(+5)⋅2−3

(−3)⋅3=(+5)⋅2

3(−3)=(+5)⋅2

=19

7 0
3 years ago
A street sign is 9 feet 9 inches tall. How tall is it in inches?
sveta [45]

Answer: Hello, There! your Answer is Below.

117 Inches

Step-by-step explanation:

An inch is a unit of length equal to exactly 2.54 centimeters. There are 12 inches in a foot, and 36 inches in a yard

A foot is a unit of length equal to exactly 12 inches or 0.3048 meters.

<em>Hope this helps you!!!</em>

<em>Have a great day!!!</em>

3 0
3 years ago
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BRAILLEST just help me answer
NikAS [45]

Answer:

Hello! What are the questions? You can type them in Comments and I will edit my answer :)

Step-by-step explanation:

3 0
3 years ago
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Is the ratio 25 to 16 proportianal to the ratio 5 to 4
vagabundo [1.1K]

Answer:

No, they aren't proportional.

Step-by-step explanation:

To simplify a ratio, you have to find the common greatest factors between both variables on each side. In this case, 25:16 is the simplist form and could never be minimized to 5:4.

3 0
3 years ago
Determine whether the improper integral converges or diverges, and find the value of each that converges.
Marina86 [1]

Answer:

Divergent.

Step-by-step explanation:

We have been given an integral \int\limits^\infty _1 {\frac{1}{x^{0.999}} \, dx. We are asked to determine whether the given integral diverges or converges.

\int _1^{\infty }\:\:\:\frac{1}{x^{0.999}}\:\:\:dx

\int _1^{\infty }\:\:\:\frac{1}{x^{0.999}}\:\:\:dx=\int _1^{\infty }\:\:\:x^{-0.999}\:\:\:dx

\int _1^{\infty }\:\:\:x^{-0.999}\:\:\:dx=\frac{x^{-0.999+1}}{-0.999+1}

\int _1^{\infty }\:\:\:x^{-0.999}\:\:\:dx=\frac{x^{0.001}}{0.001}

\int _1^{\infty }\:\:\:x^{-0.999}\:\:\:dx=1000x^{0.001}

Let us compute the boundaries.

1000(\infty)^{0.001}=\infty

1000(1)^{0.001}=1000

Since \infty-1000 is not a finite number, therefore, the given integral diverges.

4 0
3 years ago
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