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4 years ago

Solve: 2x-7>3 or 4-x≤-4

Mathematics

2 answers:

SOVA2 [1]4 years ago

7 0

Steps to solve:

2x - 7 > 3

~Add 7 to both sides

2x > 10

~Divide 2 to both sides

x > 5

Steps to solve:

4 - x <= -4

~Subtract 4 to both sides

-x <= -8

~Divide -1 to both sides

x >= 8

Best of Luck!

fredd [130]4 years ago

3 0

Answer:

2x-7>3 -----> x>5

4-x≤-4 ------> x $\geq$ 8

Step-by-step explanation:

2x-7>3

2x-7+7>3+7

2x>10

2x/2 > 10/2

x>5

4-x≤-4

4-x-4 $\leq$ -4-4

-x $\leq$ -8

(-x)(-1) $\geq$ (-8) (-1)

x $\geq$ 8

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klemol [59]

Answer:

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Step-by-step explanation:

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4 0

3 years ago

Find two consecutive odd integers whose sum is 116 (and please have steps) thank you

matrenka [14]

It's 57 and 59
Call (n) is the first odd interger => the second odd interger is (n+2)
=> n + (n + 2) = 116
=> n + n + 2 = 116
=> 2n = 114
=> n = 57
First odd interger is 57 and the second odd interger is 59 .
Sorry my English so bad =)))

6 0

4 years ago

-27=x-15 please someone help me

nadezda [96]

Answer: x = −12

Step-by-step explanation:

−27 = x −15

x − 15 = −27

x − 15 + 15 = −27 + 15

x = −12

5 0

3 years ago