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3 years ago

Solve: 2x-7>3 or 4-x≤-4

Mathematics

2 answers:

SOVA2 [1]3 years ago

7 0

Steps to solve:

2x - 7 > 3

~Add 7 to both sides

2x > 10

~Divide 2 to both sides

x > 5

Steps to solve:

4 - x <= -4

~Subtract 4 to both sides

-x <= -8

~Divide -1 to both sides

x >= 8

Best of Luck!

fredd [130]3 years ago

3 0

Answer:

2x-7>3 -----> x>5

4-x≤-4 ------> x $\geq$ 8

Step-by-step explanation:

2x-7>3

2x-7+7>3+7

2x>10

2x/2 > 10/2

x>5

4-x≤-4

4-x-4 $\leq$ -4-4

-x $\leq$ -8

(-x)(-1) $\geq$ (-8) (-1)

x $\geq$ 8

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Assume the hold time of callers to a cable company is normally distributed with a mean of 5.5 minutes and a standard deviation o

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Answer:

The percent of callers are 37.21 who are on hold.

Step-by-step explanation:

Given:

A normally distributed data.

Mean of the data, $\mu$ = 5.5 mins

Standard deviation, $\sigma$ = 0.4 mins

We have to find the callers percentage who are on hold between 5.4 and 5.8 mins.

Lets find z-score on each raw score.

⇒ $z_1=\frac{x_1-\mu}{\sigma}$ ...raw score, $x_1$ = $5.4$

⇒ Plugging the values.

⇒ $z_1=\frac{5.4-5.5}{0.4}$

⇒ $z_1=-0.25$

For raw score 5.5 the z score is.

⇒ $z_2=\frac{5.8-5.5}{0.4}$

⇒ $z_2=0.75$

Now we have to look upon the values from Z score table and arrange them in probability terms then convert it into percentages.

We have to work with P(5.4<z<5.8).

⇒ $P(5.4$

⇒ $P(-0.25$

⇒ $P(z$

⇒ $z(1.5)=0.7734$ and $z(-0.25)=0.4013$ ...from z -score table.

⇒ $0.7734-0.4013$

⇒ $0.3721$

To find the percentage we have to multiply with 100.

⇒ $0.3721\times 100$

⇒ $37.21$ %

The percent of callers who are on hold between 5.4 minutes to 5.8 minutes is 37.21

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Answer:

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Step-by-step explanation:

here's your solution

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7 0

3 years ago

Read 2 more answers