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krek1111 [17]
3 years ago
11

3²+26+

absmiddle" class="latex-formula">-625
Mathematics
1 answer:
Lena [83]3 years ago
6 0

Answer:

−590+5√5

^-^hope this helped^-^

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the first term of an arithmetic sequence is 10 and the sum of the first five terms is 250,find the sequence​
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Answer:

The  sequence  is:

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Step-by-step explanation:

We have,

First term (a) = 10

Common difference (d) = ?

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or, \frac{n}{2} [{2a+(n-1)d}] = 250

or, \frac{5}{2} [2*10 + 4d]=250

or, \frac{5}{2} * 4[5+d]=250

or, 10(5 + d) =250

or, 5 + d = 25

∴ d = 20

Now,

2nd term = a + d = 10 + 20 = 30

3rd term = a + 2d = 10 + 2*20 = 10 + 40 = 50

4th term = a + 3d = 10 + 3*20 = 10 + 60 = 70

5th term = a + 4d = 10 + 4*20 = 10 + 80 = 90

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