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777dan777 [17]
3 years ago
9

What is the height of the shape?

Mathematics
1 answer:
Kamila [148]3 years ago
3 0
23.5 you super dddddddddddddddddddddddddddddddddddddddd
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Sketch the graph of the inequality.
Bingel [31]

Answer: D. Check Desmos for confirmation. Its your best friend for Graphing.

Step-by-step explanation:

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3 years ago
Which function has zeros at x = 10 and x = 2? A f(x) = x2 – 12x + 20 B f(x) = x2 – 20x + 12 C f(x) = 5x2 + 40x + 60 D f(x) = 5x2
kow [346]
You have to set it up as two problems then combined like terms then add them together 

8 0
2 years ago
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Sa = 2(pi)(r)(h) + 2(pi)(r^2) v = (pi)(r^2)(h) find the surface area and the volume.
LenKa [72]

If Sa=2πrh+2πr^{2}v=πr^{2}h then the surface area is πr^{2} h and volume is

(rh-2h)/2r.

Given Sa=2πrh+2πr^{2} v=πr^{2}h.

We have to find surface area and volume from the given expression.

Volume is basically amount of substance a container can hold in its capacity.

First we will find the value of v from the expression. Because they are in equal to each other, we can easily find the value of v.

2πrh+2πr^{2}v=πr^{2}h

Keeping the term containing v at left side and take all other to right side.

2πr^{2}v=πr^{2}h-2πrh

v=(πr^{2}h-2πrh)/2πr^{2}

v=πr^{2} h/2πr^{2}-2πrh/2πr^{2}

v=h/2-h/r

v=h(r-2)/2r

Put the value of v in Sa=2πrh+2πr^{2} v

Sa=2πrh+2πr^{2}*h(r-2)/2r

=2πrh+2πrh(r-2)/2

=2πrh+πrh(r-2)

=2πrh+πr^{2}h-2πrh

=πr^{2}h

Hence surface area is πr^{2}h and volume is h(r-2)/2.

Learn more about surface area at brainly.com/question/16519513

#SPJ4

6 0
2 years ago
Can you help <br> me I’m not very smart
Vikentia [17]

Answer:

here u go

Step-by-step explanation:

5 0
3 years ago
5 + 1 7/8 and explain answer
anzhelika [568]

Answer:

6 7/8

Step-by-step explanation:

To evaluate 5 + 1 7/8 we combine the integers 5 and 1 and to this sum add the fraction 7/8:

5 + 1 + 7/8 = 6 7/8 (six and seven eighths)

8 0
2 years ago
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