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3 years ago

Write the fraction as a percent 3/50

Mathematics

2 answers:

katen-ka-za [31]3 years ago

8 0

Answer:

The fraction given is $\frac{3}{50}$

Step-by-step explanation:

Percent [math] definition:

Percent ---> per-hundred, or out of one-hundred

So if percent is out of one hundred, then our work should look like this:

$\frac{3}{50} = \frac{x}{100}$

x represents the missing number.

How did we get from 50 to 100?

We multiplied 50 by 2 [50 × 2], and that gave us 100.

Rule: whatever we do to the denominator, we must do to the numerator.

So if we multiplied 50 by 2 to get 100, we must multiply 3 by 2 to get x.

What is the value of x?

The value of x is 6, because 3 × 2 = 6.

So,

$\frac{3}{50} = \frac{x}{100}$

$\frac{3}{50} = \frac{6}{100}$

I hope this helps!

<h2>PLEASE MARK BRAINLIEST!</h2>

Furkat [3]3 years ago

7 0

Answer:How much is - 3 out of 50 written as a percentage? Convert fraction (ratio) - 3 / 50 Answer: - 6%

Step-by-step explanation:

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A town has 5000 people in year t = 0. Calculate how long it takes for the population P to double once, twice, and three times, a

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Step-by-step explanation:

At the time t = 0, population of the town = 5000

Rate of population increase = 500 per year

Therefore, the equation that will represent the population will be

$P_{t}=P_{0}+500t$

Where $P_{t}$ = Population after t years

$P_{0}$ = Initial population

t = Time in years

a). For double once the population will be 500×2 = 10000

By plugging in the values in the equation,

10000 = 5000 + 500t

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t = $\frac{5000}{500}$

t = 10 years

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Population will be = 10000×2 = 20000

Now we plug in the values in the equation again

20000 = 5000 + 500t

500t = 20000 - 5000

500t = 15000

t = $\frac{15000}{500}$

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Population of the town = 20000×2 = 40000

Now we plug in the values in the equation,

40000 = 5000 + 500t

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500t = 35000

t = $\frac{35000}{500}$

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b). If the population growth is 5%.

Then the growth will be exponential represented by

$T_{n}=T_{0}(1+\frac{r}{100})^{t}$

$T_{n}$ = Population after t years

$T_{0}$ = Initial population

t = time in years

For double once,

Population after t years = 10000

$10000=5000(1+\frac{5}{100})^{t}$

$(1.05)^{t}=\frac{10000}{5000}$

$(1.05)^{t}=2$

Take log on both the sides

$log(1.05)^{t}=log2$

tlog(1.05) = log2

t = $\frac{log2}{log1.05}$

t = 14.20 years

For double twice,

Population after t years = 20000

$20000=5000(1+\frac{5}{100})^{t}$

$(1.05)^{t}=\frac{20000}{5000}$

$(1.05)^{t}=4$

Take log on both the sides

$log(1.05)^{t}=log4$

tlog(1.05) = log4

t = $\frac{log4}{log1.05}$

t = 28.413 years

For double thrice

Population after t years = 40000

$40000=5000(1+\frac{5}{100})^{t}$

$(1.05)^{t}=\frac{40000}{5000}$

$(1.05)^{t}=8$

Take log on both the sides

$log(1.05)^{t}=log8$

tlog(1.05) = log8

t = $\frac{log8}{log1.05}$

t = 42.620 years

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