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ElenaW [278]
3 years ago
8

Hilary made an origami dog. What is the area of the

Mathematics
1 answer:
Rus_ich [418]3 years ago
7 0

Answer: 9.44 cm

Step-by-step explanation:

A = b × h

A = 4 × 2.36

A = 9.44 cm

To find the area of a parallelogram, the formula to use is A = b × h.

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Express the complex number in trigonometric form.<br> -6 + 6 sqrt3 i
11Alexandr11 [23.1K]

Answer:

The trigonometric form of the complex number is 12(cos 120° + i sin 120°)

Step-by-step explanation:

* Lets revise the complex number in Cartesian form and polar form

- The complex number in the Cartesian form is a + bi

-The complex number in the polar form is r(cosФ + i sinФ)

* Lets revise how we can find one from the other

- r² = a² + b²

- tanФ = b/a

* Now lets solve the problem

∵ z = -6 + i 6√3

∴ a = -6 and b = 6√3

∵ r² = a² + b²

∴ r² = (-6)² + (6√3)² = 36 + 108 = 144

∴ r = √144 = 12

∵ tan Ф° = b/a

∴ tan Ф = 6√3/-6 = -√3

∵ The x-coordinate of the point is negative

∵ The y-coordinate of the point is positive

∴ The point lies on the 2nd quadrant

* The measure of the angle in the 2nd quadrant is 180 - α, where

  α is an acute angle

∵ tan α = √3

∴ α = tan^-1 √3 = 60°

∴ Ф = 180° - 60° = 120°

∴ z = 12(cos 120° + i sin 120°)

* The trigonometric form of the complex number is

  12(cos 120° + i sin 120°)

 

4 0
3 years ago
Read 2 more answers
Which expression is equal to 2sqrt-32?
wariber [46]

Answer:

a

Step-by-step explanation:

2\sqrt{-32} \\=2\sqrt{(-1)(32)} \\=2\sqrt{-1}\sqrt{2^5} \\=2\sqrt{-1} \sqrt{(2^4)(2)} \\=2(2^2)i\sqrt{2} \\=8i\sqrt{2}

8 0
3 years ago
Use compatible numbers to estimate the quotient 19.45 divided by 4.52
son4ous [18]

Answer: 4.3

Step-by-step explanation: 4.3 is a compatible number if you divide it by both 4.3

4 0
3 years ago
5 x + 4y= 16<br> X+y = 3.5<br><br> Find out what each letter is equal to <br> X=<br> Y=
klemol [59]
X=4
Y=-0.5

Do you need an explanation?
5 0
4 years ago
Can any one please Help with 4
FrozenT [24]

Answer: i believe they are compared to knights

5 0
4 years ago
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