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rewona [7]
3 years ago
9

Andy multiplied 675times22 and got​ 2,700. Glenn multiplied the same numbers and got​ 14,850. Which student is​ correct? What mi

stake did the other student​ make? Glenn is correct. Andy multiplied nothing by 2 two times. He should have multiplied nothing by 2 and then by nothing to find the partial products.
Mathematics
1 answer:
Luden [163]3 years ago
8 0

Answer:

Glenn is correct.Andy multiplied 675 by 2 two times.

Step-by-step explanation:

We are given that Andy multiplied 675 times 22 and got=2700

Glenn multiplied 675 by 22 and got=14850

We have to find the student which is correct and find the mistake of other student.

When 675 multiplied by 22

Then , 675\times 22=14,850

Therefore, correct answer is 14,850.

Hence, Glenn is correct.

675\times 2\times 2=2700

Therefore, Andy makes mistake in calculation. .Andy did multiplied 675 by 2 two times .

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i f N(-7,-1) is a point on the terminal side of ∅ in standard form, find the exact values of the trigonometric functions of ∅.
Natali [406]

Answer:

sin\ \varnothing = \frac{-1}{10}\sqrt 2

cos\ \varnothing = \frac{-7}{10}\sqrt 2

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Step-by-step explanation:

Given

N = (-7,-1) --- terminal side of \varnothing

Required

Determine the values of trigonometric functions of \varnothing.

For \varnothing, the trigonometry ratios are:

sin\ \varnothing = \frac{y}{r}       cos\ \varnothing = \frac{x}{r}       tan\ \varnothing = \frac{y}{x}

cot\ \varnothing = \frac{x}{y}       sec\ \varnothing = \frac{r}{x}       csc\ \varnothing = \frac{r}{y}

Where:

r^2 = x^2 + y^2

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r = \sqrt{(-7)^2 + (-1)^2

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r = 5 \sqrt 2

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sin\ \varnothing = \frac{-1}{5\sqrt 2}

Rationalize:

sin\ \varnothing = \frac{-1}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}

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cos\ \varnothing = \frac{-7\sqrt 2}{10}

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tan\ \varnothing = \frac{y}{x}

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tan\ \varnothing = \frac{1}{7}

cot\ \varnothing = \frac{x}{y}

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sec\ \varnothing = \frac{r}{x}

sec\ \varnothing = \frac{5\sqrt 2}{-7}

sec\ \varnothing = \frac{-5}{7}\sqrt 2

csc\ \varnothing = \frac{r}{y}

csc\ \varnothing = \frac{5\sqrt 2}{-1}

csc\ \varnothing = -5\sqrt 2

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