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FrozenT [24]
2 years ago
14

Show me the steps of this 0.49×3.5

Mathematics
1 answer:
labwork [276]2 years ago
7 0
1 2
2 4
0.49
x 3.5
______
245
1470
+_____
1.715

note : cross out the 2 & 4 on top of .49


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YO PLS HELP ASAP !!! MARKIN <br>BRAINIEST !!! btw da drop down answers are da same as whats shown​
ale4655 [162]

Answer:

1. Is

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8 0
3 years ago
The sum to infinity of a geometric sequence is twice the first term. What is<br> the common ratio?
Dovator [93]

Answer:

The constant factor between consecutive terms of a geometric sequence is called the common ratio.

Example:

To find the common ratio , find the ratio between a term and the term preceding it. r=42=2. 2 is the common ratio.

6 0
2 years ago
How do i solve this problem
Vladimir79 [104]
Solve the following system:
{6 t - 5 s = -4 | (equation 1)
{-r - 4 s + 3 t = -4 | (equation 2)
{-2 r - 4 s - 4 t = -9 | (equation 3)

Swap equation 1 with equation 3:
{-(2 r) - 4 s - 4 t = -9 | (equation 1)
{-r - 4 s + 3 t = -4 | (equation 2)
{0 r - 5 s + 6 t = -4 | (equation 3)
Subtract 1/2 × (equation 1) from equation 2:
{-(2 r) - 4 s - 4 t = -9 | (equation 1)
{0 r - 2 s + 5 t = 1/2 | (equation 2)
{0 r - 5 s + 6 t = -4 | (equation 3)
Multiply equation 1 by -1:
{2 r + 4 s + 4 t = 9 | (equation 1)
{0 r - 2 s + 5 t = 1/2 | (equation 2)
{0 r - 5 s + 6 t = -4 | (equation 3)
Multiply equation 2 by 2:
{2 r + 4 s + 4 t = 9 | (equation 1)
{0 r - 4 s + 10 t = 1 | (equation 2)
{0 r - 5 s + 6 t = -4 | (equation 3)
Swap equation 2 with equation 3:
{2 r + 4 s + 4 t = 9 | (equation 1)
{0 r - 5 s + 6 t = -4 | (equation 2)
{0 r - 4 s + 10 t = 1 | (equation 3)
Subtract 4/5 × (equation 2) from equation 3:
{2 r + 4 s + 4 t = 9 | (equation 1)
{0 r - 5 s + 6 t = -4 | (equation 2)
{0 r+0 s+(26 t)/5 = 21/5 | (equation 3)

Multiply equation 3 by 5:
{2 r + 4 s + 4 t = 9 | (equation 1)
{0 r - 5 s + 6 t = -4 | (equation 2)
{0 r+0 s+26 t = 21 | (equation 3)
Divide equation 3 by 26:
{2 r + 4 s + 4 t = 9 | (equation 1)
{0 r - 5 s + 6 t = -4 | (equation 2)
{0 r+0 s+t = 21/26 | (equation 3)
Subtract 6 × (equation 3) from equation 2:
{2 r + 4 s + 4 t = 9 | (equation 1)
{0 r - 5 s+0 t = (-115)/13 | (equation 2)
{0 r+0 s+t = 21/26 | (equation 3)
Divide equation 2 by -5:
{2 r + 4 s + 4 t = 9 | (equation 1)
{0 r+s+0 t = 23/13 | (equation 2)
{0 r+0 s+t = 21/26 | (equation 3)
Subtract 4 × (equation 2) from equation 1:
{2 r + 0 s+4 t = 25/13 | (equation 1)
{0 r+s+0 t = 23/13 | (equation 2)
{0 r+0 s+t = 21/26 | (equation 3)
Subtract 4 × (equation 3) from equation 1:
{2 r+0 s+0 t = (-17)/13 | (equation 1)
{0 r+s+0 t = 23/13 | (equation 2)
{0 r+0 s+t = 21/26 | (equation 3)
Divide equation 1 by 2:
{r+0 s+0 t = (-17)/26 | (equation 1)
{0 r+s+0 t = 23/13 | (equation 2)
v0 r+0 s+t = 21/26 | (equation 3)
Collect results:Answer:  {r = -17/26
               {s = 23/13                        {t = 21/26
7 0
3 years ago
The value of a car decreases about 7% percent each year after it is manufactured.The 2017 Honda Civic costs $19,540
Kitty [74]

Answer: a) , where 'A' is the value of car after 't' years.


b) $12446.784



Step-by-step explanation:


Given: A new car that sells for $21,000 depreciates (decreases in value) 16% each year.


Then a function that models the value of the car will be


, where 'P' is the selling price of car, 'r' is the rate of depreciation in decimal, 't' is the time in years and 'A' is the value of car after 't' years.


Thus after substituting given value, the function becomes




To find the value after 3 years, substitute t=3 in the above function.




Hence the value of car after 3 years=$12446.784



5 0
3 years ago
19. Use the unit circle to find the value of tan 315º.<br> Show work pls.
Free_Kalibri [48]

Answer: -1

Step-by-step explanation:

First change tan(315) to:

\frac{\sin(315)}{\cos(315)}

Then evaluate the sine and cosine function. What is the y component of 315 degrees? What is the x component of 315 degrees?

-\frac{\sqrt{2} }{2} /\frac{\sqrt{2} }{2} =-1

7 0
3 years ago
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