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Artyom0805 [142]

3 years ago

9

Someone help pretty please!

1 answer:

Nonamiya [84]3 years ago

4 0

The answer is choice B
y > (2/3)x + 1

The boundary line is the equation y = (2/3)x + 1 which can be found through the slope formula to get m = 2/3. Then you use one of the two points on the line to find b = 1.

The equal sign in y = (2/3)x + 1 changes to a "greater than" sign to indicate two things
A) The shaded region is above the boundary line
B) The boundary line itself is a dashed line to indicate "no solution points on this line"

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For safety reasons, the manufacturer of a ladder recommends that it be used in such a way that the base of the ladder is no fart

professor190 [17]

See attached picture for better understanding of the problem. In the problem, the given values are the following:
hypotenuse = length of the ladder
adjacent = base of the ladder to base of the wall
Solving the angle x, we have the solution as below:
cos x = adjacent / hypotenuse
cos x = 91 / 350
x = 74.93°

The answer is 74.93°.

6 0

3 years ago

What is the intermediate step in the form (x + a)2 = b as a result of completing the

Eddi Din [679]

Answer:

(x + 7)^2 = 64

Step-by-step explanation:

x^2 + 23x – 19 = 9x - 4

x^2 + 23x - 9x = -4 + 19

x^2 + 14x = 15 = 0

Completing the square:

(x + 14/2)^2 - (14/2)^2 = 15

(x + 7)^2 - 49 = 15

(x + 7)^2 = 64

8 0

3 years ago

For exercise after work, Albert (A) went running and Tanisha (T) walked for exercise. Their times and distances are shown in the

melomori [17]

Answer:

c

Step-by-step explanation:

7 0

3 years ago

Plz help with this question

Vlad [161]

Answer:

We have been given a function and its graph.

$y=4 sin(3t)+2$

The first point should be midline of the given function

We can see the coordinate of the midline which is (-3.14,2) will be the first point.

And second point should be maximum or minimum.

So, there is minimum according to the graph.

The minimum point will be at when $sin3t=-1$

$3t=sin^{-1}(-1)$

$\Rightarrow 3t=-sin^{-1}(1)$

$\Rightarrow 3t=-\frac{\pi}{2}$

$\Rightarrow t=-\frac{\pi}{6}$

$\frac{\pi}{6}=-\frac{1.57}{3}$

So, the minimum point is: $(-\frac{1.57}{3},-2)$

3 0

3 years ago

HELP ASAP PLEASE !! :) TYSMM FOR HELPING

Mazyrski [523]

Answer:

The answer is C.

4 0

4 years ago