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Hitman42 [59]
3 years ago
8

A scientist was measuring the daily sodium values of different foods with a soda has 35.64% of the daily value and fries have 32

.9% of the daily value how much would they have together
Mathematics
1 answer:
uysha [10]3 years ago
4 0

Answer:

68.54

Step-by-step explanation:

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Find the output for the graph<br> y = -6x + 25<br> when the input value is 3.<br> =<br> y = [?]
avanturin [10]

<u><em>Answer</em></u>

x=\frac{11}{3}

<u><em>Explanation</em></u>

Based on the given conditions, formulate:: y=3

Substitute y=3 into y=-6x+25 :: 3=-6x+25

Rearrange variables to the left side of the equation: 6x=25-3

Calculate the sum or difference: 6x=22

Divide both sides of the equation by the coefficient of variable: x=\frac{22}{6}

Cross out the common factor: x=\frac{11}{3}

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2 years ago
The original price of a skateboard, not including tax, was $96. Charlie bought the skateboard on sale, and he saved 30% off of t
Lady_Fox [76]

Answer:

$67.20

Step-by-step explanation:

"30% off" translates into multiplying the original price by 1.00 - 0.30, or 0.70.

0.70($96) = $67.20 is the sales price

4 0
3 years ago
3,471 into scientific notation
anzhelika [568]

Answer:

3.471 x 10^3

hope i helped

3 0
3 years ago
A study has shown that the daily amount of milk produced by a dairy cow is normally distributed, with a mean of 6.2 gallons and
V125BC [204]

Answer:

5.5 gallons to 6.9 gallons

Step-by-step explanation:

Daily a cow

produces a mean of 6.2 gallons (average

of 6.2 gallons, meaning they already

found the mean, "averaged" it out for

you) with a deviation of 7 gallons ("give

or take" .7 gallons). On any given day

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Just subtract the deviation ("give or

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(average (already determined)) 6.2

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the deviation ("give or take number").

7 gallons to the mean (average (already

determined)) 6.2 gallons which is 6.9

gallons. Your answer is A 5.5 gallons to

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crazy on the math on this question you

can rule them all out but A immediately

with subtracting .7 from 6.2.

hope it helps!

4 0
3 years ago
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