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3 years ago

If you flip 2 coins, what is the probability of getting exactly 2 heads

Mathematics

2 answers:

Ahat [919]3 years ago

4 0

Answer:

This states that the probability of the occurrence of two independent events is the product of their individual probabilities. The probability of getting two heads on two coin tosses is 0.5 x 0.5 or 0.25.

Step-by-step explanation:

The probability of getting 2 heads with 2 coins can be broken into 2 steps:

The first coin must show Heads AND

the second coin must show Heads.

p(h,h)= P(H) <----- and means multiply

P(H) x P(H)= 1/2 x 1/2 =1/4

natulia [17]3 years ago

3 0

What the first guy said

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Consider the spreading of a rumor through a company of 1000 employees, allworking in the same building.We assume that the spread

natima [27]

Answer:

On the 12th day, the rumor would have has to all the 1000 employees

Step-by-step explanation:

Given the data in the question;

so, lets consider the rumor spreading thorough the company of 1000 employee;

the given model is; $r_{n+1}$ = $r_{n}$ + 1000k $r_{n}$ ( 1000 - $r_{n}$ )

where k is the parameter that depends on how fast the rumor spreads, n is the number of days.

now, lets assume k = 0.0001, lets also assume r₀ = 4

so to find how soon all 1000 employees will have heard the rumor ;

let n be;

then r1 will be;

r1 = r₀ + ( 0.001)r₀(1000-r₀ )

r1 = 4 + ( 0.001) × 4× (1000 - 4 )

r1 = 7.984

r2 will be;

r2 = r1 + ( 0.001)r1(1000-r1 )

r2 = 7.984 + ( 0.001) × 7.984 × (1000 - 7.984 )

r2 = 15.904255744

r3 will be;

r3 = r2 + ( 0.001)r2(1000-r2 )

r3 = 15.904255744 + ( 0.001) × 15.904255744 × (1000 - 15.904255744 )

r3 = 31.555566137

Using the same formula and procedure by substituting n = 1,2,3,4,5,6,7,8,9,10,11,12.

we will have;

n rₙ

0 4

1 7.984

2 15.904255744

3 31.555566137

4 62.1153785

5 120.372437

6 226.25535

7 401.319217

8 641.58132

9 871.53605

10 983.497013

11 999.727651

12 999.999926

Therefore, On the 12th day, the rumor would have has to all the 1000 employees

5 0

3 years ago

Maddie bought 3 2/3 yards of satin ribbon at the craft store. She wanted to make hair bows for the cheer squad. Each bow require

kotegsom [21]

Answer:

Step-by-step explanation:

Given that:

Total yards of satin bought by Maddie = $3\frac{2}{3}$ yards

Number of yards required make one ribbon = $\frac{2}{3}$ yards

To find:

Number of complete bows that can be made ?

Solution:

First of all, let us learn about converting the mixed fraction to fractional form.

Formula:

$a\dfrac{b}{c} = \dfrac{a\times c+b}{c}$

Therefore, total yards of satin bought by Maddie can be written in fractional form as:

$3\dfrac{2}{3} = \dfrac{3\times 3+2}{3} = \dfrac{11}{3}$

One hair bow requires $\frac{2}{3}$ yards of ribbon.

Number of hair bows that can be made, can be found by dividing the total ribbon length by ribbon required for making one hair bow.

Answer is:

$\dfrac{\frac{11}{3}}{\frac{2}{3}}\\\Rightarrow \dfrac{11\times 3}{2\times 3}\\\approx 4$

4 hair bows can be made.

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Gre4nikov [31]

Your answer is d
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Fiesta28 [93]

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Eva8 [605]

Answer:

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Step-by-step explanation:

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