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balandron [24]
3 years ago
10

What is the hypotenuse of a triangle with 4 ft and 5 ft

Mathematics
1 answer:
sergeinik [125]3 years ago
8 0

Answer:

\Large\text{The hypotenuse is}\ \sqrt{41}\ ft\approx6.4\ ft

Step-by-step explanation:

\text{Use the Pythagorean theorem:}

a^2+b^2=c^2

\text{a, b - legs}\\\text{c - hypotenuse}

\text{We have the legs 4ft and 5ft. Substitute:}

c^2=4^2+5^2\\\\c^2=16+25\\\\c^2=41\to c=\sqrt{41}

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Answer:

The radius of the circles are 4\ m  and   8\ m

Step-by-step explanation:

Let

x-----> the radius of larger circle

y----> the radius of smaller circle

we know that

\pi x^{2} +\pi y^{2}=80\pi

x^{2} +y^{2}=80 -----> equation A

Remember that

x=2y -----> equation B

substitute equation B in equation A and solve for y

(2y)^{2} +y^{2}=80

4y^{2} +y^{2}=80

5y^{2}=80

y^{2}=16

y=4\ m

Find the value of x

x=2y

x=2(4)=8\ m

therefore

The radius of the circles are 4\ m  and   8\ m

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Step-by-step explanation:

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Step-by-step explanation:

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