What is the hypotenuse of a triangle with 4 ft and 5 ft

Mathematics

1 answer:

sergeinik [125]3 years ago

8 0

Answer:

$\Large\text{The hypotenuse is}\ \sqrt{41}\ ft\approx6.4\ ft$

Step-by-step explanation:

$\text{Use the Pythagorean theorem:}$

$a^2+b^2=c^2$

$\text{a, b - legs}\\\text{c - hypotenuse}$

$\text{We have the legs 4ft and 5ft. Substitute:}$

$c^2=4^2+5^2\\\\c^2=16+25\\\\c^2=41\to c=\sqrt{41}$

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Two angles are complementary angles if the sum of their measure is 90 degrees. Angle A and angle B are complementary angles, and

Marta_Voda [28]

Let's solve this problem step-by-step.

STEP-BY-STEP SOLUTION:

We will be using simultaneous equations to solve this problem.

First we will establish the equations which we will be using as displayed below:

Equation No. 1 -

A + B = 90°

Equation No. 1 -

A = 2B + 12

To begin with, let's make ( A ) the subject in the first equation as displayed below:

Equation No. 1 -

A + B = 90

A = 90 - B

Next we will substitute the value of ( A ) from the first equation into the second equation and solve for ( B ) as displayed below:

Equation No. 2 -

A = 2B + 12

( 90 - B ) = 2B + 12

- B - 2B = 12 - 90

- 3B = - 78

B = - 78 / - 3

B = 26°

Then we will substitute the value of ( B ) from the second equation into the first equation to solve for ( A ) as displayed below:

A = 90 - B

A = 90 - ( 26 )

A = 64°

ANSWER:

Therefore, the answer is:

A = 64°

B = 26°

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4 0

3 years ago

Un carpintero quiere cortar una plancha de triple y de 1m de largo y 60 cm de ancho, en cuadrados lo más grandes posibles. El ca

Ugo [173]

Answer: $20\ cm$