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3 years ago

If f(x) = |x| + 9 and g(x) = –6, which describes the value of (f + g)(x)?

Mathematics

2 answers:

tangare [24]3 years ago

6 0

(f+g)(x) ≥ 3 for all values of x

Greeley [361]3 years ago

6 0

Answer:

$|x|+3$

Step-by-step explanation:

We have been given two functions $f(x)=|x|+9$ and $g(x)=-6$ . We are asked to find the value of $(f+g)(x)$ .

To find the value of $(f+g)(x)$ we need to add both of our given functions.

$(f+g)(x)=f(x)+g(x)$

Upon substituting the values of both functions we will get,

$(f+g)(x)=|x|+9+(-6)$

$(f+g)(x)=|x|+9-6$

$(f+g)(x)=|x|+3$

Therefore, the value of our given composite function $(f+g)(x)$ will be $|x|+3$ .

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I GIVE ANOTHER BRAINLIEST

dlinn [17]

Answer:

Answer Below

Step-by-step explanation:

Triangle #1

To solve this answer we need to multiply then divide by 2

$3$ x $8=24$

$24$ ÷ $2=12$

Triangle #2

Now we do the same thing!

$3$ x $8=24$

$24$ ÷ $2=12$

Rectangle #1

Now we solve for the rectangle!

$6$ x $8 = 48$

Now we add all these together!

$12 + 12 + 48 = 72$

The answer is D. 72 Square Units

8 0

2 years ago

Read 2 more answers

What does 3/216 simplify to

quester [9]

216 divided by 3 is 72 so making the answer

1/72

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3 years ago

How to do the math for the following questions

agasfer [191]

88.21 fram is the anserer

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3 years ago

Assume that when adults with smartphones are randomly selected, 52% use them in meetings or classes. If 14 adult smartphone us

emmasim [6.3K]

The probability that fewer than 4 of then use their smart phones in meetings or classes is 0.00030243747.

Step-by-step explanation:

Fewer than 4 means ,less than 4 which is any number less than 4 and not including 4. This is 3, 2,1 and 0. So you find the probability that exactly 3 of then use their smart phone, exactly 2 of them use their smart phones, exactly 1 of them use his/her smart phone and none of them.

Given that 52% use smartphones in meetings and classes =0.52

Thus the remaining 48% do not use smartphones in meetings and classes=0.48

For C(14,3) you will have "14 chose 3", number of ways of choosing 3 out of 14'

=(0.52)³ *(0.48)⁹=0.00019018714

For C(14,2) you will have "14 chose 2", number of ways of choosing 2 out of 14

=(0.52)²*(0.48)¹²=0.00004044841

For C(14,1) you will have "14 chose 1", number of ways of choosing 1 out of 14

=(0.52)¹*(0.48)¹³=0.000037337

For C(14,0) you will have "14 chose 0", number of ways of choosing 0 out of 14

=(0.52)⁰*(0.48)¹⁴=1*0.00003446492=0.00003446492

The probability that fewer than 4 of them use their smartphones in meetings or classes will be

0.00019018714 +0.00004044841+0.000037337+ 0.00003446492=0.00030243747

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Binomial random variable https://brainly.in/question/10088120

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4 0

3 years ago

A design engineer wants to construct a sample mean chart for controlling the service life of a halogen headlamp his company prod

tekilochka [14]

Answer:

C) 515 hours.

D) 500 hours

c) sample 3

Step-by-step explanation:

1. Sample 2 mean = x2`= ∑x2/n2= 2060/4= 515 hours

Sample Service Life (hours)

1 2 3

495 525 470

500 515 480

505 505 460

500 515 470

∑2000 2060 1880

x1`= ∑x1/n1= 2000/4= 500 hours

x2`= ∑x2/n2= 2060/4= 515 hours

x3`= ∑x3/n3= 1880/4= 470 hours

2. The mean of the sampling distribution of sample means for whenever service life is in control is 500 hours . It is the given mean in the question and the limits are determined by using μ ± σ , μ±2 σ or μ ± 3 σ.

In this question the limits are determined by using μ ± σ .

3. Upper control limit = UCL = 520 hours

Lower Control Limit= LCL = 480 Hours

Sample 1 mean = x1`= ∑x1/n1= 2000/4= 500 hours

Sample 2 mean = x2`= ∑x2/n2= 2060/4= 515 hours

Sample 3 mean = x3`= ∑x3/n3= 1880/4= 470 hours

This means that the sample mean must lie within the range 480-520 hours but sample 3 has a mean of 470 which is out of the given limit.

We see that the sample 3 mean is lower than the LCL. The other two means are within the given UCL and LCL.

This can be shown by the diagram.

8 0

2 years ago