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8_murik_8 [283]
3 years ago
10

a nationwide study of american homeowners revealed that​ 65% own at least one lawn mower. a lawn equipment​ manufacturer, locate

d in​ charlotte, feels that this estimate is too low for households in charlotte. to support his​ claim, he randomly selects 497 homes in charlotte and finds that 340 had one or more lawn mowers. find the​ p-value for testing the claim that the proportion of homeowners owning lawn mowers in charlotte is higher than​ 65%. round your answer to three decimal places. when you calculate the sample proportion keep 4 decimal places.
Mathematics
1 answer:
svetoff [14.1K]3 years ago
4 0

Answer:

z=\frac{0.6841 -0.65}{\sqrt{\frac{0.65(1-0.65)}{497}}}=1.5938  

We have a right tailed test then the p value would be:  

p_v =P(z>1.5938)=0.0555  

Step-by-step explanation:

Information provided

n=497 represent the random sample of homes selected

X=340 represent the number of homes with one or more lawn

\hat p=\frac{340}{497}=0.6841 estimated proportion of homes with one or more lawn

p_o=0.65 is the value that we want to test

z would represent the statistic

p_v represent the p value (variable of interest)  

System of hypothesis

We want to check if proportion of homeowners owning lawn mowers in charlotte is higher than​ 65%m so then the correct hypothesis are .:  

Null hypothesis:p\leq 0.65  

Alternative hypothesis:p > 0.65  

The statistic is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing the info given we got:

z=\frac{0.6841 -0.65}{\sqrt{\frac{0.65(1-0.65)}{497}}}=1.5938  

We have a right tailed test then the p value would be:  

p_v =P(z>1.5938)=0.0555  

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Ok here is a better pic I need help with it​
BartSMP [9]

Answer:

Step-by-step explanation:

First,You have to realize that if you multiply the amount of food by something, you multiply the amount of calories.  if some piece of food is 100 calories what happens if you eat 2?  you get 2 times that number of calories.  Same fi you eat half of one of that kind of food.  You get half the amount of calories.

Here he makes 1 1/2 (one and a half) times the amount.  Now, if this is confusing  you just need to realize that  multiplying by this is the same as multiplying by 1+1/2.  Say, again, a piece of food is 100 calories.  Multiplying it by this would look like the following.

100(1+1/2)

100*1 + 100*1/2

100+50

150

So if you ever have a mixed number like this  you could split it up into an addition problem and then distribute hat you're multiplying.  Another solution is to multiply by the improper fraction, which here is 3/2, so 100*3/2=150 as well.  Let me know if you don't get how to get the improper fraction or how to multiply fractions.

Now, super simple, just multiply the calories by that number.

310(1+1/2) = 310(3/2)

310 + 155 = 930/2

465 = 465

Kinda showed how to multiply by fractions, still if you don't get it let me know.  

6 0
3 years ago
How do you solve this problem?
enot [183]
Easy, it says "for ANY positive integer" so just test any positive integer

remember that n! means times all integers from 1 to that number n

lets try 1

(1+1)!/(1!)-1=
(2!)/(1!)-1=
2/1-1=
2-1=
1

if you don't believe me, try 2
(2+1)!/(2!)-2=
(3!)/(2!)-2=
(6)/(2)-2=
3-2=
1

te answer is 1, B


and number 9
easy, remember the exponential law
(x^m)(x^n)=x^(m+n)
jsut add the exponents
first gropu like bases
(r^2r^2/3)(t^1/2t^-3/2)
add bases
(r^2 and 2/3)(t^-1)=
(r^2∛(r^2))(1/t)=
\frac{r^{2} \sqrt[3]{r^{2}} }{t}
5 0
3 years ago
What is the volume of the composite figure. I said 36 but it is wrong.
scZoUnD [109]

Answer:

108

Step-by-step explanation:

You are correct for stating one tissue box has a volume for 36.

But notice there are 3 tissue boxes, so in order to find the total volume, you should add them up.

36+36+36=108

6 0
3 years ago
Read 2 more answers
1 USD is 1.37 CAD 86 CAR is how many USD
laiz [17]

Answer:

67.64

Step-by-step explanation:

6 0
2 years ago
What is the percent decrease from 60 to 39?
IrinaK [193]
X - the percent decrease

60-60x=39 \ \ \ |-60 \\
-60x=-21 \ \ \ |\div (-60) \\
x=\frac{-21}{-60} \\ \Downarrow \\ x=\frac{-21}{-60}=\frac{-21 \div (-3)}{-60 \div (-3)}=\frac{7}{20}=\frac{7 \times 5}{20 \times 5}=\frac{35}{100}=35\%

It's a 35% decrease.
7 0
3 years ago
Read 2 more answers
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