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ella [17]
3 years ago
9

Given A(2,1), B(3,3), and scale factor: 4, graph the image and pre-image under the given dilation. Label the endpoints.

Mathematics
1 answer:
GrogVix [38]3 years ago
7 0

Answer:

  see below

Step-by-step explanation:

Each image coordinate is 4 times the corresponding pre-image coordinate.

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Answer:

7, true, sextic binomial

Step-by-step explanation:

highest degree is 7, it is a monomial, 6th degree two terms.

8 0
3 years ago
6 = 2p + 8 pls help i will give brainlist
Y_Kistochka [10]

Answer:

6 = 2p + 8 \\  \\ 2p + 8 = 6 \\  \\ 2p = 6 - 8 \\  \\ 2p =  - 2 \\  \\ p =   -  \frac{2}{2}  \\  \\ p =  - 1

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2 years ago
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Wjejennensnssjahashkh
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3 years ago
I have one more question before im done so please help and have a good day.
3241004551 [841]

Answer:

  • See below

Step-by-step explanation:

<h3>Part A</h3>

<u>Solve the equation:</u>

  • 6x² + 48x + 120 = 0
  • x² + 8x + 20 = 0
  • x² + 8x + 16 + 4 = 0
  • (x + 4)² + 4 = 0
  • (x + 4)² = - 4

The left side is positive and right side is negative so no solution

<h3>Part B</h3>

There is no intercession with the x-axis, the graph of the function is entirely above the x-axis.

It means the diver won't reach the bottom of the lake

6 0
2 years ago
√₂
snow_lady [41]

Answer:

$2000 was invested at 5% and $5000 was invested at 8%.

Step-by-step explanation:

Assuming the interest is simple interest.

<u>Simple Interest Formula</u>

I = Prt

where:

  • I = interest earned.
  • P = principal invested.
  • r = interest rate (in decimal form).
  • t = time (in years).

Given:

  • Total P = $7000
  • P₁ = principal invested at 5%
  • P₂ = principal invested at 8%
  • Total interest = $500
  • r₁ = 5% = 0.05
  • r₂ = 8% = 0.08
  • t = 1 year

Create two equations from the given information:

\textsf{Equation 1}: \quad \sf P_1+P_2=7000

\textsf{Equation 2}: \quad \sf P_1r_1t+P_2r_2t=I\implies 0.05P_1+0.08P_2=500

Rewrite Equation 1 to make P₁ the subject:

\implies \sf P_1=7000-P_2

Substitute this into Equation 2 and solve for P₂:

\implies \sf 0.05(7000-P_2)+0.08P_2=500

\implies \sf 350-0.05P_2+0.08P_2=500

\implies \sf 0.03P_2=150

\implies \sf P_2=\dfrac{150}{0.03}

\implies \sf P_2=5000

Substitute the found value of P₂ into Equation 1 and solve for P₁:

\implies \sf P_1+5000=7000

\implies \sf P_1=7000-5000

\implies \sf P_1 = 2000

$2000 was invested at 5% and $5000 was invested at 8%.

Learn more about simple interest here:

brainly.com/question/27743947

brainly.com/question/28350785

5 0
1 year ago
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