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DIA [1.3K]
4 years ago
8

Convert 3/11 to decimal equivalent using long division

Mathematics
1 answer:
sergey [27]4 years ago
7 0
So simple... 3\ll=27\100 which equals 27.0 or 0.27
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Evaluate √ 9.6230 * 2.340 / 5.3 10 * 3.721​
adoni [48]

Answer:

\sqrt{15.76}

Step-by-step explanation:

\sqrt{9.6230 \frac{2.340}{5.310}3.721 }

Lets solve the fraction first

\frac{2.340}{5.310} =0.44

9.6230 x 0.44 = 4.23

4.23 x 3.721 = 15.76

\sqrt{15.76}

7 0
3 years ago
Sin70° cos80° + cos70° sin80°​
kirill [66]
The answer for your question is (1/2) and alternate form is 0.5 and 2^-1
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3 years ago
SI LOS ELEMENTOS DE UN CONJUNTO PERTENECEN TODOS A OTRO CONJUNTO SE LLAMAN: a) Iguales b) Subconjunto c) Cardinalidad
Liono4ka [1.6K]

Answer:

B; Subconjunto

Step-by-step explanation:

Aquí, se nos pide que seleccionemos el término que define un conjunto con sus elementos que pertenecen a un conjunto más grande.

La respuesta correcta es que el conjunto más pequeño es un subconjunto del conjunto más grande.

Esto significa que el conjunto más pequeño es parte del conjunto más grande, lo que lo convierte en una subdivisión del conjunto más grande

6 0
4 years ago
Factorise the following : ​
Free_Kalibri [48]

Answer:

(3x+4b)(a-2y)

Step-by-step explanation:

(3ax-6xy)+(8by-4ab)

3x(a-2y) -4b(-2y+a)

(3x+4b) (a-2y)

4 0
3 years ago
Read 2 more answers
What is the slope of the line? <br><br> As soon as possible please !!
mixer [17]

Answer:

m=\frac{-8}{5}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Slope Formula: m=\frac{y_2-y_1}{x_2-x_1}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Find points from graph.</em>

Point (-1, 4)

Point (4, -4)

<u>Step 2: Find slope </u><em><u>m</u></em>

  1. Substitute [Slope Formula]:                    m=\frac{-4-4}{4+1}
  2. Subtract/Add:                                          m=\frac{-8}{5}
5 0
3 years ago
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