Answer:
Time required is 1.33 seconds
Explanation:
For first order reaction, the rate law expression is:
![kt = ln \frac{[A_{0}]}{[A_{t}]}](https://tex.z-dn.net/?f=kt%20%3D%20ln%20%5Cfrac%7B%5BA_%7B0%7D%5D%7D%7B%5BA_%7Bt%7D%5D%7D)
Where
A0 = initial concentration = 0.830 M
At = concentration after time t = 0.260 M
t = time in seconds = ?
k = rate constant = 0.870 s⁻¹
time = ](https://tex.z-dn.net/?f=%5B%5Cfrac%7B1%7D%7Bk%7D%5D%28ln%5B%5Cfrac%7B0.830%7D%7B0.260%7D%5D%29)
time = 
If the total amount of the sample is 230g and they give each component of the sample, we add the given amount of grams of each element and subtract the given from 230g.
That means the rest of oxygen is 35.2g
This is Percent Composition.
The formula to find the percent composition of an element inside a compound is
Now we implement the variables into the formula to find the percent composition oxygen.
The answer is <span>
15.30% = O</span>
Answer:
BaCl2+ 2NaOH=2NaCl+Ba(OH)2
Explanation:
If you need an explanation on how I balanced it then let me know
Answer:
75 mg
Explanation:
We can write the extraction formula as
x = m/[1 + (1/K)(Vaq/Vo)], where
x = mass extracted
m = total mass of solute
K = distribution coefficient
Vo = volume of organic layer
Vaq = volume of aqueous layer
Data:
m = 75 mg
K = 1.8
Vo = 0.90 mL
Vaq = 1.00 mL
Calculations:
For each extraction,
1 + (1/K)(Vaq/Vo) = 1 + (1/1.8)(1.00/0.90) = 1 + 0.62 = 1.62
x = m/1.62 = 0.618m
So, 61.8 % of the solute is extracted in each step.
In other words, 38.2 % of the solute remains.
Let r = the amount remaining after n extractions. Then
r = m(0.382)^n.
If n = 7,
r = 75(0.382)^7 = 75 × 0.001 18 = 0.088 mg
m = 75 - 0.088 = 75 mg
After seven extractions, 75 mg (99.999 %) of the solute will be extracted.
Answer:
Law of Conservation of Mass.
Is that Right?
