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Fittoniya [83]
4 years ago
7

Which scientist’s law about the ratios of masses of elements in a compound did John Dalton’s work on the atomic structure help t

o explain?
Democritus
J. J. Thomson
Ernest Rutherford
Joseph Proust
Chemistry
2 answers:
PIT_PIT [208]4 years ago
7 0

Answer is: Joseph Proust.

Proust's law or law of constant composition said that a given chemical compound always contains its component elements in fixed ratio and does not depend on method of preparation.

Law of multiple proportions or Dalton's Law said that the ratios of the masses of the second element which combine with a fixed mass of the first element will be ratios of small whole numbers.

For example, nitrogen(I) oxide N₂O; m(N) : m(O) = 2·14 : 16 = 7 : 4.

sweet [91]4 years ago
5 0
<span>the awnser is d Joseph Proust 

</span>
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Consider the gas-phase reaction, Cl2(g) + Br2(g) &lt;=&gt; 2 BrCl(g), for which Kp = 32 at 500 K. If the mixture is analyzed and
goldfiish [28.3K]

Answer:

  • <em><u>a) Q > K and more reactants will be made to reach equilibrium</u></em>

Explanation:

The reaction quotient, Q, is the actual ratio of concentrations or pressure of products to reactants.

When Q is equal to the equilibrium constant, the reaction is at equilibrium.

When Q > K, the concentrations, or pressures, of the products will have to decrease to reach the equilibrium, thus more reactants will be made.

When Q < K the concentrations, or pressures, of the reactants will have to decrease to reach the equilibrium, thus more products will be made.

Calculate Q:

  • Reaction equation: Cl₂(g) + Br₂(g) ⇄ 2 BrCl(g),

         P_{Cl_2}}=0.19bar\\\\P_{Br_2}}=0.29bar\\\\P_{BrCl}=1.4bar

        Q=\dfrac{(P_{BrCl})^2}{(P_{Br_2}).(P_{Cl_2})}

        Q=\dfrac{(1.4bar)^2}{(0.19bar).(0.29bar)}

        Q\approx 36

Therefore, since <em>Q > K</em>, the pressure of the products should decrease to reach the equilibrium, meaning that <em>more reactants will be made</em>, i.e. option a).

8 0
4 years ago
What mass of K2SO4 would you measure out to prepare 550 ml of a 0.76 M solution
Nikolay [14]
The molecular weight of K2SO4 is 174.26 g/mole. The mass of K2SO4 required to make this solution is calculated in the following way. 
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<span>I hope this helps.</span>
5 0
3 years ago
Read 2 more answers
Mass-mass problem:
ValentinkaMS [17]

Answer:

17.05 g of glucose

Explanation:

The equation of the reaction is given as;

6CO2 + 6H2O → C6H12O6 + 602

From the equation;

6 mol of CO2 produces 1 mol of  C6H12O6

Converting to masses;

CO2:

Mass =Number of moles * Molar mass

Mass = 6 mol * 44 g/mol = 264 g

C6H12O6:

Mass =  Number of moles * Molar mass

Mass = 1 mol * 180 g/mol = 180 g

This means 264g of CO2 produces 180g of C6H12O6

25g of CO2 would produce x g of C6H12O6

264 = 180

25 = x

x = 25 * 180 / 264

x = 17.05 g

6 0
3 years ago
Circle the letter of each sentence that is true about units of volume.
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I was unable to come up with an answer but I still wanted to help so heres a site that'll give you your answer.  http://chemed.chem.purdue.edu/genchem/topicreview/bp/ch1/index.php
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